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2 years ago

What number should be added to −5/11to get 26/33?

1 answer:

4 0

41/33 should be added to -15/33 (which is the same number as -5/11 but converted to have same denominator).
So answer is 41/33

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In the figure, Line a is parallel to line b. Name the angles congruent to angle 3.

disa [49]

Go with what u think will help u

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2 years ago

This table on a package of dog food tells how much to feed a dog, depending on its weight. Weight of Dog (pounds)153045 Amount

Novay_Z [31]

9514 1404 393

Answer:

k = 2/15

Step-by-step explanation:

We can solve the given equation for k:

k = s/p . . . . . . divide the given equation by p on both sides

Using the first values from the table (15 pounds, 2 scoops), we have ...

k = 2/15

The value of k is 2/15.

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2 years ago

The solution set for the equation x - 6x + 10 = 0 is

Oxana [17]

Answer:

{3-i, 3+ i}

Step-by-step explanation:

hello : the equation is : x²-6x+10 =0

because : (3+i)²-6(3+i)+10 = 9+6i+i²-18-6i+10 =9+6i-1-18-6i+10 =0...right

same method for 3-i... (all quadratic equation have two conjugate solution)

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2 years ago

Can I get help please

WITCHER [35]

Answer:

sorry you cant get help but you can help me!

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Step-by-step explanation:

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2 years ago

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w

Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds. Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

$t = 5.0625$

Step-by-step explanation:

Given

$h(t)=-16t^2+80t+5$

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

$0=-16t^2+80t+5$

Reorder

$-16t^2+80t+5 = 0$

Using quadratic formula, we have:

$t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

Where

$a = -16$ $b =80$ $c = 5$

So, we have:

$t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}$

$t = \frac{-80\±\sqrt{6400 +320}}{-32}$

$t = \frac{-80\±\sqrt{6720}}{-32}$

$t = \frac{-80\±82.0}{-32}$

This gives:

$t = \frac{-80+82.0}{-32}$ or $t = \frac{-80-82.0}{-32}$

$t = \frac{2}{-32}$ or $t = \frac{-162}{-32}$

$t = -\frac{2}{32}$ or $t = \frac{162}{32}$

But time can not be negative.

So, we have:

$t = \frac{162}{32}$

$t = 5.0625$

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0

2 years ago