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3 years ago

What number should be added to −5/11to get 26/33?

1 answer:

4 0

41/33 should be added to -15/33 (which is the same number as -5/11 but converted to have same denominator).
So answer is 41/33

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2) 8xy -- 3y + 2 ( 9x - 5y + 4 ) if x = 3, y = - 4

Scilla [17]

Answer:

8xy-3y + 2(9x-5y+4) = 18

Step-by-step explanation:

We need to find the value of the given expression:

8xy-3y + 2(9x-5y+4) ....(1)

when x = 3 and y = -4

Put the values of a and y in equation (1)

8×3×(-4)-3(-4)+ 2(9×3-5(-4)+4)

= -96 +12 + 2(27 + 20 +4)

= -84 + 2(51)

= -84 + 102

= 18

Hence, the value of the given expression is 18.

4 0

3 years ago

I have to solve for x in a diagram. it is a right triangle, cut into a smaller right triangle and a trapezoid. The cut measure 6

tensa zangetsu [6.8K]

The answer is in the picture

3 0

3 years ago

At which root does the graph of f(x) = (x + 4)(x + 7,5) cross the x-axis? -7 -4 4 7

Alona [7]

Answer:

Answer: -7

Step-by-step explanation:

5 0

2 years ago

g A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estim

kipiarov [429]

Answer:

a) n= 1045 computers

b) n= 442 computers

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

Step-by-step explanation:

Hello!

The variable of interest is

X: Number of computers that use the new operating system.

You need to find the best sample size to take so that the proportion of computers that use the new operating system can be estimated with a 99% CI and a margin of error no greater than 4%.

The confidence interval for the population proportion is:

p' ± $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

$Z_{1-\alpha /2}= Z_{0.995}= 2.586$

a) In this item there is no known value for the sample proportion (p') when something like this happens, you have to assume the "worst-case scenario" that is, that the proportion of success and failure of the trial are the same, i.e. p'=q'=0.5

The margin of error of the interval is:

d= $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

$\frac{d}{Z_{1-\alpha /2}} = \sqrt{\frac{p'(1-p)}{n} }$

$(\frac{d}{Z_{1-\alpha /2}})^2 = \frac{p'(1-p')}{n}$

$n * (\frac{d}{Z_{1-\alpha /2}})^2 = p'(1-p')$

$n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2$

$n=[0.5(1-0.5)]*(\frac{2.586}{0.04} )^2= 1044.9056$

n= 1045 computers

b) This time there is a known value for the sample proportion: p'= 0.88, using the same confidence level and required margin of error:

$n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2$

$n= [0.88*0.12]*(\frac{{2.586}}{0.04})^2= 441.3681$

n= 442 computers

c) The additional information in part b affected the required sample size, it was drastically decreased in comparison with the sample size calculated in a).

I hope it helps!

4 0

4 years ago

R=2/3t +v...solve for t...thanks

mote1985 [20]

$\dfrac{2}{3}t+v=r\ \ \ |subtract\ v\ from\ both\ sides\\\\\dfrac{2}{3}t=r-v\ \ \ \ |multiply\ both\ sides\ by\ \dfrac{3}{2}\\\\\boxed{t=\frac{3}{2}(r-v)}$

4 0

3 years ago

Read 2 more answers