All categories

3 years ago

+

Mathematics

1 answer:

Zarrin [17]3 years ago

4 0

Please reformat your question so that I can try to help.

You might be interested in

Which expressions are equivalent to 4^3 x 4^-5? Choose all answers that are correct. A) 4^-2 B) 1/16 C) 4^-15 D) 0.0625 E) 16^-1

astraxan [27]

The given expression is

$4^3 * 4^{-5}$

Here we have to use the product rule of exponent, according to which in case of multiplication, we have to add the exponents, that is

$4^3 * 4^{-5} = 4^{3-5} = 4^{-2}$

So out of the given options, correct option is A .

7 0

3 years ago

What is the quotient of -36 and -3

Greeley [361]

12
Since there's two negatives, the answer is going to be positive. Do regular division.
36 / 3
=12

7 0

3 years ago

Read 2 more answers

What is the solution to the equation 3x + 2(x − 9) = 8x + x − 14? (1 point)

solong [7]

Answer:

B. -1

Step-by-step explanation:

STEP 1: Simplify 3x+2(x−9).

$5x-18=8x+x-14$

STEP 2: Add 8x and x.

$5x-18=9x=-14$

STEP 3: Move all terms containing x to the left side of the equation.

$-4x-18=-14$

STEP 3: Move all terms not containing x to the right side of the equation.

$-4x=4$

STEP 4: Divide each term by −4 and simplify.

$x=-1$

6 0

3 years ago

1. Find the slope of the line that passes through the points (9, 7) and (2, 9).

Lesechka [4]

Answer:

Step-by-step explanation:

Slope of line passing through (x₁, y₁) and (x₂, y₂) = (y₂-y₁)/(x₂-x₁)

Slope of line passing through (9, 7) and (2, 9) = (9-7)/(2-9) = -2/7

3 0

3 years ago

Read 2 more answers

The areas of the squares adjacent to two sides of a right triangle are 32units^2 and 32 units^2

adoni [48]

Answer:

x = 8 units.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em>The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle</em>

My answer:

Let a is the side length of the 1st square

The area of the 1st square is equal to 32 units square

<=> $a^{2} = 32$

<=> a = $4\sqrt{2}$ units

Let b is the length of the 2nd square

The area of the 2nd square is equal to 32 units square

<=> $b^{2}$ = 32

<=> b = $4\sqrt{2}$ units

Find the value of x

Applying the Pythagoras Theorem, we have:

$x^{2} = a^{2} + b^{2}$

<=> $x^{2} = 32 + 32$

<=> $x^{2} = 64$

<=> x = 8 units

Hope it will find you well.

4 0

3 years ago

Read 2 more answers