Given:
Cards labelled 1, 3, 5, 6, 8 and 9.
A card is drawn and not replaced. Then a second card is drawn at random.
To find:
The probability of drawing 2 even numbers.
Solution:
We have,
Even number cards = 6, 8
Odd numbers cards = 1, 3, 5, 9
Total cards = 1, 3, 5, 6, 8 and 9
Number of even cards = 2
Number of total cards = 6
So, the probability of getting an even card in first draw is:
![P_1=\dfrac{\text{Number of even cards}}{\text{Number of total cards}}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B%5Ctext%7BNumber%20of%20even%20cards%7D%7D%7B%5Ctext%7BNumber%20of%20total%20cards%7D%7D)
![P_1=\dfrac{2}{6}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B2%7D%7B6%7D)
![P_1=\dfrac{1}{3}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B1%7D%7B3%7D)
Now,
Number of remaining even cards = 1
Number of remaining cards = 5
So, the probability of getting an even card in second draw is:
![P_2=\dfrac{\text{Number of remaining even cards}}{\text{Number of remaining total cards}}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B%5Ctext%7BNumber%20of%20remaining%20even%20cards%7D%7D%7B%5Ctext%7BNumber%20of%20remaining%20total%20cards%7D%7D)
![P_2=\dfrac{1}{5}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B1%7D%7B5%7D)
The probability of drawing 2 even numbers is:
![P=P_1\times P_2](https://tex.z-dn.net/?f=P%3DP_1%5Ctimes%20P_2)
![P=\dfrac{1}{3}\times \dfrac{1}{5}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D)
![P=\dfrac{1}{15}](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B1%7D%7B15%7D)
Therefore, the probability of drawing 2 even numbers is
. Hence, the correct option is (b).
Answer:
5 peices of pizza for $4 each
and 4 drinks for $2
Step-by-step explanation:
Answer:
What equation are we supposed to simplify?
Theres no equation
He currently does 8, and is increasing by 2, so our equation will be
2x+8=30
Subtract the 8 over
2x=22
Divide by 2 on both sides
X=11
It will take 11 days