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nikklg [1K]
2 years ago
8

The coordinate grid below shows triangle ABC and its image after translation, triangle A'B'C':

Mathematics
1 answer:
svetlana [45]2 years ago
8 0

Answer:

+6 B

Step-by-step explanation:

Which of the following completes the rule for this translation, (x, y) + (x + 6, )?

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Help me!! Find the area of this figure.​
Nezavi [6.7K]

Answer:

510

Step-by-step explanation:

divide into chunks. I divided it like how you would draw the equal sign.

for top chunk, 20*8=160

for 2nd chunk, 8*25=200

for the last chunk, 15*10=150

add up 160, 200, and 150

8 0
3 years ago
Read 2 more answers
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.
kherson [118]

Answer:

  • A.)  (3.6, 0.6)
  • D.)  (2.6, 0.4)

Step-by-step explanation:

See below for a graph.

___

Choices B, C, E can be eliminated on the basis that neither x nor g(x) can be negative. The domain of f(x) is x>0; the range of g(x) is x≥0.

7 0
2 years ago
2. Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes
jasenka [17]

Answer:

Natural numbers (integers greater than zero)

X = 3,  5,  4,  4,  3

Step-by-step explanation:

The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.

The possible values of X are integers greater than zero, which are known as the Natural numbers.

If X = number of cars observed, simply count the number of letters in each outcome for the value of X:

Outcome = RRL, AARRL, AARL, RRAL, ARL

            X = 3,  5,  4,  4,  3

7 0
3 years ago
A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}

The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

7 0
3 years ago
Amanda's computer weighs 20 ounces. How many pounds does it weigh?
Natali5045456 [20]

Answer: 1.25

Step-by-step explanation:

Convert it lol I don’t know how to say it? But also you can look it up if needed

6 0
3 years ago
Read 2 more answers
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