Answer:
510
Step-by-step explanation:
divide into chunks. I divided it like how you would draw the equal sign.
for top chunk, 20*8=160
for 2nd chunk, 8*25=200
for the last chunk, 15*10=150
add up 160, 200, and 150
Answer:
- A.) (3.6, 0.6)
- D.) (2.6, 0.4)
Step-by-step explanation:
See below for a graph.
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Choices B, C, E can be eliminated on the basis that neither x nor g(x) can be negative. The domain of f(x) is x>0; the range of g(x) is x≥0.
Answer:
Natural numbers (integers greater than zero)
X = 3, 5, 4, 4, 3
Step-by-step explanation:
The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.
The possible values of X are integers greater than zero, which are known as the Natural numbers.
If X = number of cars observed, simply count the number of letters in each outcome for the value of X:
Outcome = RRL, AARRL, AARL, RRAL, ARL
X = 3, 5, 4, 4, 3
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation

Solve for S(t):


The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:



There's no sugar in the water at the start, so (a) S(0) = 0, which gives

and so (b) the amount of sugar in the tank at time t is

As
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Answer: 1.25
Step-by-step explanation:
Convert it lol I don’t know how to say it? But also you can look it up if needed