Answer: Q= 6x+1
R= -7x+1
Step-by-step explanation:
Answers:
A. 1c/2lb
B. 8 cups of dressing
SOLUTION
Given that a catering company’s recipe for Salad uses a
ratio of 2c of dressing to 4 lb of vegetables
A. Write a ratio of dressing to vegetables as a reduced
fraction
A reduced fraction is the expression of a ratio in its simplest
fractional form
Dressing: Vegetable = 2c : 4 lb
In fractional form,
2c/4lb
2 is a common factor to both numerator and denominator
Therefore, in reduced fractional form,
2c/4lb = 1c/2lb
Therefore, ratio of dressing to vegetables as a reduced
fraction is 1c/2lb
B. How many cups of dressing would they need for 16 lb of
vegetables
1c = 2lb
16lb = ?
Since 1c = 2lb
2lb = 1c
1lb = 1/2 c
16lb = 16(1/2)c
16lb = 8c
Therefore, they would need 8 cups of dressing for 16 lb of
vegetables
Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x
<h3>Variation</h3>
y = k × x
4 = k × 2
4 = 2k
k = 4/2
k = 2
when y = 2 and x = 4
y = k × x
= 2 × 4
y = 8
y = k/x
4 = k / 2
8 = k
when y = 2 and x = 4
y = k/x
2 = k/4
2 × 4 = k
k = 8
So,
y = k/x
y = 8/x
Learn more about variation:
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Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/
The upper limit => C.I_u = μ + Z*σ/
The lower limit => C.I_l = μ - Z*σ/
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/)
= 200 + (1.96*30)/
= 200 + 58.8/
Answer:
x = 62.23 ft
y = 47.67 ft
Step-by-step explanation: