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Vesna [10]
2 years ago
7

A cylinder has volume 72pi and radius 3. What is its height?​

Mathematics
1 answer:
kifflom [539]2 years ago
5 0

Answer:

8

Step-by-step explanation:

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Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 1
eimsori [14]

The correct option is b.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

<h2>Leading coefficient </h2>

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.)  f(x) = -12x^2+3x+1 \\

b.)  f(x) = 3x^2+11x-12 \\

c.)  f(x) = 12x^2+3x+3\\

d.)  f(x) = 3x -12.

<h3 /><h3>Solution</h3>

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

Learn more about Quadratic Equation:

brainly.com/question/2263981

8 0
2 years ago
Use the givin values to complete each table
Vilka [71]
To find the answers, substitute the variables (letters) in the equation for the number on that line that corresponds to that letter, then solve with the equation.
4 0
2 years ago
If 20% of a length is 23cm ,whathat is the complete length
Gennadij [26K]

Step-by-step explanation:

20% of the length is 23 cm

100% of the length is 23×5 = 115 cm

6 0
2 years ago
Read 2 more answers
What is the volume of this cube 2.1cm
allsm [11]

volume of cube = S^3

volume = 2.1^3

volume = 9.261 cm^3

7 0
2 years ago
Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de
Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

\to df = n - 1 = 71-1= 70

In point B:

\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to  13.335315832 = (x - 81)\\\\\to  13.335315832 +81 =x \\\\\to x= 94.335315832

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\

5 0
3 years ago
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