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Serggg [28]
3 years ago
13

Help please, its super duper easy!

Mathematics
2 answers:
Firdavs [7]3 years ago
5 0

Answer:

R would be 36.

Step-by-step explanation:

Subtract the two know angles from 180 to get your missing angle. :)

Hope this helps!

If you don't mind please mark as brainliest! :)

Thanks!!!

tresset_1 [31]3 years ago
4 0

Answer:

36 degrees

Step-by-step explanation:

Okay, so the angles of a triangle are always gonna add up to 180. So, let's add up 68 & 76.

68 + 76 = 144

Now we just have to subtract that from 180

180 - 144 = 36

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Each time there are 6 possible outcomes.

If you roll four times, the number of possible outcomes would be 6^4, or 1296.

Final answer: 1296 configurations.
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3 years ago
Write each sentence as an equation.
Montano1993 [528]

Answer:

  1. <em> n - 2 = 52</em>
  2. <em>x - 3 = 12</em>
  3. <em>5 + x = 50 - 10</em>
  4. <em>3 + x = 60</em>
  5. <em>x + 6 = 10 - 2</em>
  6. <em>x - 9 = 12</em>
  7. <em>x + 5 = 13</em>
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3 0
3 years ago
The 'Queen Mary' used to sail across the Atlantic Ocean The ships usual speed was 33 miles per hour. On average, the ship used f
makkiz [27]
13403.07692307692 i think is the answer because you multiply 5280 by 33 and then divide by 13.
6 0
3 years ago
I really need help i i put a picture up but this thing do´s not let me post it with out a question ?
kobusy [5.1K]

Answer:

Step-by-step explanation:

y=-x^{2} -5x-6

y=-(x^2+5x+6)

y=-(x+3)(x+2)

Set each factors equal to zero.

(x+3)=0 ,  x=-3

x+2=0  ,   x=-2

The x-int is

(-2,0)

4 0
2 years ago
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
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