Answer:
Not doubled
Explanation:
The equation below represent the ideal gases relationship
PV ÷ T = constant
Here
P denotes pressure,
V denotes volume,
T denotes temperature in degrees Kelvin
Now
20 ° c = 273 + 20
= 293 K
And,
40 ° c = 313 K
So,
V = Vo. 313 K ÷ 293 K = 1.07 Vo
So, the volume is NOT doubled.
In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero
Heat of vaporization (During which the temperature stays the same)
Answer:
725 mmHg
Explanation:
1 mmHg = 133,32 Pa
mmHg and Pa are both units of measurement of pressure.
Answer:
Average molecular weight of air is 28.84 g/mol.
Explanation:
The average molecular weight of a mixture is determined from their molar composition and molecular weight.
Average molecular weight :
: mole fraction of the 'i' component.
= Molecular weight of i component
Average molecular weight of air with approximate molar composition of 79% nitrogen gas and 21% of oxygen gas can be calculated as:
Average molecular weight of air:
