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3 years ago

5

A 9.86 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid. If 27.5 mL of 0.337 M potassiu

m hydroxide are required to neutralize the hydroiodic acid, what is the percent by mass of hydroiodic acid in the mixture?
% by mass

1 answer:

Aneli [31]3 years ago

7 0

Answer:

88.3% of hydroiodic acid is found

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7 × 10² pounds of Cl₂ would be produced in a typical 8-h operating day.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measures quantitative relationships and it is to calculate the amount of products and reactants that are given in a reaction.

<h3>What is Balanced chemical equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactants side is equal to the number of atoms on the product side in an equation.

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According to stoichiometry, moles of Cl₂

$= (3 \times 10^4\ A) \left (\frac{\frac{C}{s}}{A} \right ) \left (\frac{3600\ s}{h} \right ) (8h) \left (\frac{1\ \text{mol}\ e^{-}}{9.65 \times 10^4\ C} \right ) \left (\frac{1\ \text{mol}\ Cl_2}{2\ \text{mol}\ e^-} \right )$

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$= (4477\ \text{moles}\ Cl_2) \left (\frac{70.90\ g\ Cl_2}{\text{mol}} \right ) \left (\frac{1\ kg}{1000\ g} \right ) \left (\frac{2.205\ lb}{1\ kg} \right )$

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Learn more about Stoichiometry here: brainly.com/question/14935523

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