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2 years ago

Cuando un gas que se encuentra a 20°c se calienta hasta los 40°c sin que varie su presion, su volumen se duplica

Chemistry

1 answer:

kati45 [8]2 years ago

4 0

Answer:

Not doubled

Explanation:

The equation below represent the ideal gases relationship

PV ÷ T = constant

Here

P denotes pressure,

V denotes volume,

T denotes temperature in degrees Kelvin

Now

20 ° c = 273 + 20

= 293 K

And,

40 ° c = 313 K

So,

V = Vo. 313 K ÷ 293 K = 1.07 Vo

So, the volume is NOT doubled.

In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero

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3 years ago

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Answer:

Here the given material is taken and mixed with water.

Explanation:

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3 years ago

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A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt

Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

Step 1: Data given

Sample 1: The 1.15 M sample has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

Step 2: Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1: 1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

Step 3: Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams ( in 55mL)

Step 4: Calculate moles of AgBr

AgNO3 reacts with KBr

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

Step 5: Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

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3 years ago

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