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drek231 [11]
3 years ago
12

A piece of green rope is being used to make a border around the outside of a sculpture that is in the shape of an equilateral tr

iangle. One side of the equilateral triangle has a length of 3x + 3. Give TWO equivalent expressions that can be used to represent the length of the rope that is used to border all 3 sides.
Mathematics
1 answer:
damaskus [11]3 years ago
5 0

Answer:

The equivalent expressions are;

9x + 9

and

9(x + 1)

Step-by-step explanation:

Mathematically, we should understand that an equilateral triangle has all of its sides equal

So if one side is 3x+ 3, the other sides too measures same

Therefore, the length of the rope represents the perimeter of the triangle

This is obtainable by adding all the side lengths together

This will be;

3x + 3 + 3x + 3 + 3x + 3 = 9x + 9

This is also same as 9(x + 1)

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Is 640 ft greater or smaller than 0.5 miles
navik [9.2K]
1 mile = 5280 feet
0.5 mile = 5280/2 = 2640 feet
640 ft is thus smaller than 0.5 miles.
4 0
3 years ago
Convert 5,000 inches to feet
borishaifa [10]

There are 12 inches in one foot:

1 ft = 12 in

We want to find how many feet are in 5000 inches:

x ft = 5000 in

Set up a proportion:

1/12 = x/5000

Cross multiply:

12x = 5000

Divide by 12:

x is about 416.67 feet.

3 0
4 years ago
Read 2 more answers
Work out the area of the trapezium ABDE.<br> B<br> 9 cm<br> 6 cm<br> 8 cm<br> →D<br> E
Evgen [1.6K]

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

So by the property of similarity their sides will be proportional.

\frac{AE}{BD}= \frac{CE}{CD}

\frac{9}{6}=\frac{CE}{8}

CE = \frac{9\times 8}{6}

CE = 12 cm

Therefore, DE = CE - CD

DE = 12 - 8 = 4 cm

Now area of trapezium ABDE = \frac{1}{2}(AE+BD)(DE)

                                                  = \frac{1}{2}(6+9)4

                                                  = 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

8 0
3 years ago
At a given moment, a plane passes directly above a radar station at an altitude of 6 km6 km and the plane's speed is 800 km/h.80
Valentin [98]

Answer: see explanation

Step-by-step explanation:

so you have a plane at constant altitudeof 6km (6000m) flying at 800 km/h (222.222 m/s) (see the image)

the plane is moving with constant speed therefore x(t) = 222.222*t => no forces are interacting horizontally with the plane therefore acceleration is 0, then v is constant and x(t) is a linear function which coefficient is v.

now we have a triangle with an angle theta, one side is x(t), and the other is 6000m. we can get theta by tan(theta) = 6000/(222.222*t). 24 minutes are 1440 seconds so if we replace such value, we get the theta angle by  solving for theta => theta = arctan(6000/(222.222*1440)) = 0.019 radians or 1.074 degrees. Now if you want to know the exchange rate of theta we have to differentiate the expression with respect to t:

\frac{d}{dt} \theta = \frac{d}{dt}(arctan(\frac{6000}{222.222*t} )) = \frac{1}{1+\frac{6000}{222.222*t} } * -\frac{27}{t^2}  = -\frac{27}{t^2+729.001}

then replace t with 1440 and you will get that theta is changing by -0.000013 (1.3E-5) radians or -7.458E-4 degrees every second which has a lot of sense since the plane is getting out of your line of sight due to the earth's curvature

5 0
3 years ago
Please help i need this one asap
slavikrds [6]

Answer:

no

Step-by-step explanation:

Do your own work

6 0
3 years ago
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