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2 years ago

Find the exact value of (1 7/9)^1/2

Mathematics

1 answer:

sweet [91]2 years ago

3 0

I assume you mean the mixed number 1 + 7/9.

As an improper fraction, we have

1 7/9 = 1 + 7/9 = 9/9 + 7/9 = (9 + 7)/9 = 16/9

Then the square root of this is

√(1 7/9) = √(16/9) = √(4²/3²) = √((4/3)²) = 4/3

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(F x G)(x)<br> F(G(x))<br> G[F(x)]<br> F[G(x)]<br> G(F(x))

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The results of the composite functions are:

$(f \times g)(x) = 6x^2-9x$

$f(g(x)) = 6x - 3$

$g(f(x)) = 6x - 9$

<h3>What are composite functions?</h3>

Composite functions are functions that are obtained by combining two or more functions together

Assume that:

$f(x) = 2x - 3$

$g(x) = 3x$

Then the computation of the composite functions are as follows:

<h3>Function (f * g)(x)</h3>

$(f \times g)(x) = f(x) \times g(x)$

$(f \times g)(x) = (2x-3) \times (3x)$

$(f \times g)(x) = 6x^2-9x$

<h3>Function f(g(x))</h3>

We have: $f(x) = 2x - 3$

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$f(g(x)) = 2g(x) - 3$

So, we have:

$f(g(x)) = 2(3x) - 3$

$f(g(x)) = 6x - 3$

<h3>Function g(f(x))</h3>

We have: $g(x) = 3x$

This gives

$g(f(x)) = 3f(x)$

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Read more about composite functions at:

brainly.com/question/10687170

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