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Maurinko [17]
3 years ago
9

Ok last one lets get it!

Mathematics
2 answers:
hammer [34]3 years ago
4 0

Answer:

No yes no yes no

Step-by-step explanation:

RideAnS [48]3 years ago
3 0
Dallas: No
Landing: Yes
Louisville: No
Madison: Yes
Montgomery: No
You might be interested in
5=g/8 PLRASE HELP Me
pantera1 [17]

G= 40

5x8=40

40/8=5

All you have to do is inverse operations so instead of dividing you multiply your 5 and 8 to get 40 and then check your work.

4 0
3 years ago
1) Shannon and Kristoph are dividing numbers written in scientific notation.
mihalych1998 [28]

Answer:

<h3>(A)</h3>

The answers will have the same value, beacuse both scientific notations have the same coefficient, 4.2 and 1.4. Also, if you mentally subtract the exponents of those powers, you would have the same exponent. So, equal coefficient and equal exponent will give the same result.

<h3>(B)</h3>

The value of each expression can be found by dividing coefficients and powers.

\frac{4.2 \times 10^{9} }{1.4 \times 10^{4} }=3 \times 10^{9-4} = 3 \times  10^{5}

<h3>(C)</h3>

The value of each expression in standard form is

3 \times 10^{5}=300,000

Remember that standard form refers to the number without the ten-power.

5 0
4 years ago
Solve when c=7 and d=3 <br>5c-3d+11​
Studentka2010 [4]

Answer:

37

Step-by-step explanation:

5*7 is 35

3*3 is 9

35-9 is 26

26+11 is 37

6 0
3 years ago
Read 2 more answers
A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p
Kay [80]

Answer:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by V= 10 +t

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of \frac{A}{10+t}

So then we can reorder the differential equation like this:

\frac{dA}{dt} +\frac{A}{10+t} =8

We find the solution using the integration factor:

\mu = -\int \frac{1}{10+t} dt = -ln(10+t)

And then the solution would be given by:

A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})

And if we simplify this we got:

A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)

And after do the integral we got:

A= \frac{c}{10+t} +4 (10 +t)

And using the initial condition t=0 A= 20 we have this:

20 = \frac{c}{10} +40

c= -200

So then we have this function for the solution of A:

A= \frac{-200}{10+t} +4 (10 +t)

And now replacinf t= 40 we got:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

8 0
3 years ago
Which is the standard form for this number? (2 x 10) + (5 x 1) + (8 x 1 10,000 )
Veronika [31]
COMBINE LIKE TERMS
2x10+5x+80000x

(2x10)+(5x+80000x)


ANSWER
(2 x 10) + (5 x 1) + (8 x 1 10,000) = 2x10+80005x

4 0
4 years ago
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