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slavikrds [6]
4 years ago
6

manuela planted 5 patches of beans each patch has 8 rows of 27 bean plant a)how many bean plants are in each patch

Mathematics
1 answer:
vichka [17]4 years ago
4 0
The answer is 1080 hope this helped may i have brainliest
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Solve in order of operation<br> Thanks
Greeley [361]

Answer:

b=40

c=12

Step-by-step explanation:

b) 3+7(8-6)2

10(2)2

20^2 =40

C) 4+(−3) 2 −2÷( 6/3)

4+9− 2/6/3

13-2/6/3

13-2x3/6

13-6/6

13-1

c=12

​

​

​

7 0
3 years ago
Read 2 more answers
At a large university, the mean amount spent by students for cell phone service is $58.90 per month with a standard deviation of
zhenek [66]

Answer:

2.28% probability that the mean amount of their monthly cell phone bills is more than $60

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 58.90, \sigma = 3.64, n = 44, s = \frac{3.64}{\sqrt{44}} = 0.54875

What is the probability that the mean amount of their monthly cell phone bills is more than $60?

This is 1 subtracted by the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{60 - 58.90}{0.54875}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the mean amount of their monthly cell phone bills is more than $60

4 0
3 years ago
Which method is the most effective method to use to solve x^2+4x+3=0
lukranit [14]

Answer:

Completing the square.

Step-by-step explanation:

since there is no "a" term and the bx term is even, completing the square is your best bet.

6 0
3 years ago
Read 2 more answers
What is true about the solution of x^2 / 2x - 6 = 9 / 6x - 18
DanielleElmas [232]

\text{The domain}\\2x-6\neq0\ \wedge\ 6x-18\neq0\to x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2(x-3)}=\dfrac{9}{6(x-3)}\ \ \ |\cdot6\\\\\dfrac{3x^2}{x-3}=\dfrac{9}{x-3}\iff3x^2=9\ \ \ |:3\\\\x^2=3\to x=\pm\sqrt3

4 0
3 years ago
Read 2 more answers
Bob decides he wants to make guitars and sell them online. He makes and sells Gibson Explorer’s and Gibson Flying V’s. He can ma
lozanna [386]
Okay so the equation. Lets say e is explorers and v is flying vs and m = money.

e + v > or = 30.

80e + 5v =m.
 
e < or = 20\
v < or = 20.
Okay, the most money he could make would be if he made 20 explorers at 80 dollars and 10 vs at 5 dollars.
Total money...
1600 + 50 = 1650.
So he could make $1650.

7 0
3 years ago
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