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slavikrds [6]
4 years ago
6

manuela planted 5 patches of beans each patch has 8 rows of 27 bean plant a)how many bean plants are in each patch

Mathematics
1 answer:
vichka [17]4 years ago
4 0
The answer is 1080 hope this helped may i have brainliest
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What is 4(x-7)=2(x+3)?
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Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

4(x−7)=2(x+3)

Simplify both sides of the equation.

4(x−7)=2(x+3)

4x+−28=2x+6

4x−28=2x+6

Subtract 2x from both sides.

4x−28−2x=2x+6−2x

x−28=6

Add 28 to both sides.

2x−28+28=6+28

2x=34

Divide both sides by 2.

2x/2  =  34/2

x = 17

5 0
3 years ago
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In what ways does adding a constant or coefficient to a quadrationc affect the graph
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Hope this helps <span>1)   </span><span>Equations with negative values for a</span><span> produce graphs that open down and equations with a positive values for a</span> produce graphs that open up.

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3 0
3 years ago
Two out of every 5 muffins are blueberry in one muffin variety pack. how many muffins are blueberry muffins if there are a total
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Since the ratio is 2/5 then for 25 (which is five 5s) there will be 2 × 5 which is 10
Answer: there are 10 bluemuffins
3 0
3 years ago
Defined terms examples
Vera_Pavlovna [14]
A thing characteristic of its kind or illustrating a general rule
4 0
3 years ago
ank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains30 gallons of water in which 5
adell [148]

Answer:

\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}

\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}

x(0)=20,y(0)=5

Step-by-step explanation:

We are given that

Tank A contains water=80 gallons

x(0)=20,y(0)=5

Tank B contains water=30 gallons

Rate=4 gallon/min

Concentration of salt  is pumped into tank=0.5 pound /gallon of water

Solution pumped from tank A to tank B at the rate=6 gallons/min

Solution pumped from tank B to tank A at the rate=2gallon/min

Solution from tank B is pumped out of the system at the rate=4 gallon/min

We have to find the DE at time t

For x

Rate in=0.5\times 4+y(t)/30\times 2

Rate in=2+y/15

Rate out=x/80\times 6

Rate out=3x/40[/tex]

\frac{dx}{dt}=Rate in-Rate out

\frac{dx}{dt}=2+y/15-3x/40

\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}

For y

Rate in=x/80\times 6

Rate in=3/40x

Rate out=y/30\times (4+2)

Rate out=y/5

\frac{dy}{dt}=Rate in-Rate out

\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}

8 0
3 years ago
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