All categories

3 years ago

manuela planted 5 patches of beans each patch has 8 rows of 27 bean plant a)how many bean plants are in each patch

Mathematics

1 answer:

vichka [17]3 years ago

4 0

The answer is 1080 hope this helped may i have brainliest

You might be interested in

Find all real solutions and show work: 2x^3-3x^2+18x-27=0

Amiraneli [1.4K]

Given:

The given equation is

$2x^3-3x^2+18x-27=0$

To find:

All the real solutions.

Solution:

We have,

$2x^3-3x^2+18x-27=0$

It can be written as

$x^2(2x-3)+9(2x-3)=0$

$(2x-3)(x^2+9)=0$

Using zero product property, we get

$(2x-3)=0$ and $(x^2+9)=0$

$2x=3$ and $x^2=-9$

$x=\dfrac{3}{2}$ and $x=\pm\sqrt{-9}$

We know that $x=\pm\sqrt{-9}$ is an imaginary number because there is a negative sign under the square root.

Therefore, $x=\dfrac{3}{2}$ is the only real solution of the given equation.

5 0

3 years ago

23 and 24 please? Anyone?

Tasya [4]

Answer:

23. 92 points

24. 18.5 years old

Step-by-step explanation:

set up an equation

23. 79=chicago-13

add 13

chicago=79+13=92

24. 15.5=lou-3

loud=15.5+3=18.5

6 0

3 years ago

Find three fifth of Ghana cedis 200

Llana [10]

Answer:

Hi.

three fifth of 200 is 120.

4 0

3 years ago

Read 2 more answers

Which expression equals 6x − 5y + 2 − 8x + 3( y + 5)? A) 3x − 2y + 17 B) −3x + 2y + 17 C) −2x − 2y + 17 D) −2x − 2y − 17

inysia [295]

Answer:

C) −2x − 2y + 17

Step-by-step explanation (PEMDAS):

First, we do 3 (y + 5) because of the parenthesis:

6x − 5y + 2 − 8x + 3y + 15

Since there are no exponents, multiplication ,or division, we will add and subtract. But we have to make sure we combine like terms. X with X's, Y with Y's and constants with constants. And ALWAYS go from left to right

6x − 5y + 2 − 8x + 3y + 15

−2x − 5y + 2 + 3y + 15

−2x − 2y + 2 + 15

−2x − 2y + 17.

8 0

3 years ago

A number consists of two digits. The number is 2 more than 8 times the sum of the digits, and if 54 is subtracted from the numbe

Gennadij [26K]

Let the units digit = x

Let the 10s digit = y

Equations

10y + x - 2 = 8 * (x + y) (1)

10y + x - 54 = 10x + y (2)

Equation 1

10y + x - 2 = 8 * (x + y) Remove the brackets on the right

10y + x - 2 = 8x + 8y Subtract 8y from both sides

10y - 8y + x - 2 = 8x Subtract 8x from both sides

2y + x - 8x - 2 = 0 Combine

2y - 7x - 2 = 0 (3)

Equation 2

10y + x - 54 = 10x + y Subtract 10x

10y - 9x - 54 = y Subtract y from both sides.

9y - 9x - 54 = 0 Divide by 9

y - x - 6 = 0 Multiply by 2

2y - 2x - 12 = 0 (4)

Solution

Subtract (3) - (4)

2y - 7x - 2 = 0

2y - 2x - 12 = 0

- 5x + 10 = 0 Subtract 10 from both sides.

- 5x = - 10 Divide by - 5

x = 2

Use (4) to find y

2y - 2x - 12 = 0 Let x =2

2y - 2(2) - 12 = 0 Remove the brackets

2y - 4 - 12 = 0 Combine

2y - 16 = 0 Add 16 to both sides.

2y = 16 Divide by 2

y = 8

Answer 82

I'll leave the check to you, but the answer of 82 is correct.

4 0

3 years ago