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Gre4nikov [31]
3 years ago
13

What is the area of the trapezoid?

Mathematics
2 answers:
iris [78.8K]3 years ago
5 0

Answer:

c

Step-by-step explanation:

AlladinOne [14]3 years ago
3 0

Answer:

C) 84 cm2

Step-by-step explanation:

A=\frac{a+b}{2} h\\\\A=\frac{8+16}{2} *7\\\\A=\frac{24}{2} *7\\\\A=12*7\\A=84

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I just don’t understand the math
olchik [2.2K]
I believe the answer is 6
3 0
3 years ago
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By how many degrees did the direction of the boat change
gulaghasi [49]

Answer:

The boat turned <u>39°</u> degrees when it made its first turn.

Step-by-step explanation:

The question is as following:

A boat traveled north for 28 miles, then tuned x° south west and traveled for 25 miles before stopping. When it stopped, the boat was 18 miles from its starting point.

By how many degrees did the direction of the boat change when it made its first turn? Round to the nearest degree.

===================================================

See the attached figure which represent explanation of the problem.

The boat start from point A to point B then stopped at point C

AB = 28 miles, BC = 25 miles and AC = 18 miles.

It is required to find the angle x

By applying the cosine Rule:

AC² = AB² + BC² - 2 * AB * BC * cos x

18² = 28² + 25² - 2 * 28 * 25 * cos x

2 * 28 * 25 * cos x = 28² + 25² - 18²

1400 cos x = 1085

Cos x = 1085/1400 = 0.775

x = Cos⁻¹ 0.775 = 39.2° = 39° to the nearest degree.

So, the boat turned <u>39°</u> degrees when it made its first turn.

8 0
3 years ago
riya obtained the following score (out of 100) in a vocabulary test: 80,85,90,71,60,100. what is her mean score​
Greeley [361]

Answer:

85

Step-by-step explanation:

3 0
2 years ago
A picture is 46 cm by 32 cm. A scale diagram of the picture must fit in a space that is 3 m by 2 m. Which scale would be the mos
Marrrta [24]

Answer:

A picture that is 46cm by 32 cm must fit in a space that is 3m by 2m

First, let's rewrite both of these dimensions in the same units.

Knowing that:

1m = 100cm

Then the dimensions of the space can be rewritten from:

3m by 2m

to:

300cm by 200cm

So, if we enlarge our original picture by a scale factor K, the new dimensions of the picture will be:

K*46cm by K*32cm

Now we just need to find a value of K such that:

K*46cm is something near to 300cm

K*32cm is something near to 200cm

First, we can solve the equation:

K*46cm = 300cm

solving this for K we get:

K = 300cm/46cm = 6.5

While if we solve the equation:

K*32cm = 200cm

we get:

K = 200cm/32cm = 6.25

So we got two possible scale factors.

Which one we should take?

Notice that if we wanted to use the larger one (K = 6.5) for the 32cm side. the new length would be:

32cm*6.5 = 208cm

This is larger than the 200cm of space that we have

Then we can not select the larger option, we can only take the other value:

K = 6.25

Then we can conclude that a reasonable scale factor to use is K = 6.25

4 0
2 years ago
Find the sum (3x^2+5x-8)+(5x^2-13x-5)
Radda [10]
<span>8x^2-8x-13 is the correct answer </span>
3 0
3 years ago
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