Given
Brian's house: (-7, 9)
Sue's house: (-7, -2)
Find
The number of units between Brian's house and Sue's house.
Solution
Both Brian and Sue live on the "street" x=-7, so the distance between their houses is the distance between -2 on that street and +9 on that street. We always consider distance to be positive, so it doesn't matter whether we start at Brian's house and go -11 units to Sue's house, or start at Sue's house and go +11 units to Brian's house. Either way, we travel 11 units.
_____
"Displacement" is another matter. That has a sign associated with it and there is always a reference direction that is positive. Movement in the opposite direction results in a negative displacement. "Distance" is always positive.
In this case just change the variables by the numbers. (1,5)
x=1 y=5
1^2 + 5^2 = 26
1+25=26
26=26 *this one is the answer...
TRUE
x2 + y2 = 16
1^2 + 5^2=16
1+25=16
26=16
False
x2 + y2 = 13
1^2 + 5^2=13
1+25=13
26=13
False
x2 + y2 = 11
1^2 + 5^2=11
1+25=11
26=11
False
So we can say that the first one is the answer.
Answer:
oh so for one get them to look alike.. sooo keep 5/16 and change 1 7/8 to
1 14/16 and then change it to 30/16 then simply compare 5 can go into 30 6 times soooooo it can go into 1 & 7/8 6 times
Step-by-step explanation:
Answer:
Length of AB is 8cm
Step-by-step explanation:
It is a Pythagorean triple; 6,8,10
That is,
AB=√AD²-BD²
AB=√10²-6²
AB=√100-36=√64=8units
F(x) = 2x -3 g(x) = -4x+6
g(x) = K f(x)
- 4x+6 = K( 2x-3) ⇒ K= -2
verification
-2 ( 2x-3 ) = - 4x + 6
