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Mila [183]
3 years ago
5

Eighth grade

Mathematics
1 answer:
Ymorist [56]3 years ago
7 0

Answer:

b = 1

Step-by-step explanation:

Given the equation is:

- 5b + 2b - (-b) + 7 = 5

We separate the terms of b and the constants. To do that we subtract 7 from both the sides. We get:

- 5b + 2b - (-b) + 7 - 7 = 5 - 7

⇒ - 5b + 2b - (-b) = - 2

Now, simplifying the terms with 'b'.

⇒ -5b + 2b + b = - 2

⇒ (-5 + 2 + 1)b = - 2

⇒ -2b  = -2

Dividing both the sides by -2, we get:

b = 1 which is the required answer.

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Scale on a map is 1:800000. motorway is 120 km long . what distance will it be on the map​
Rudik [331]

Answer:

Multiply the number of inches on the map times the scale to determine the true distance. For example, if the distance on the map was 5.5 inches and the scale was 1:6,336,000, the true distance would be 550 miles. To convert an area, convert the dimensions using the scale and then find the true area.

7 0
3 years ago
What are the slopes of the two lines? <br> green has two yellow dots.
IrinaVladis [17]

Answer:

-7(1/7) = -1

Step-by-step explanation:

4 0
3 years ago
Batman (mass=100 kg) jumps straight down from a bridge in to a boat (mass = 580 kg) in which a criminal is fleeing. The velocity
Crank

Answer:

v_b=11.94\ m/s

Step-by-step explanation:

<u>Linear Momentum </u>

The momentum of a system of masses m1,m2,m3... with speeds v1,v2,v3,... is given by

M=m_1v_1+m_2v_2+m_3v_3+...

When some interactions take place into the system of masses with no external forces interferring, the total momentum is not changed, which means that if the new speeds are v1', v2', v3'... then:

m_1v_1+m_2v_2+m_3v_3+...=m_1v_1'+m_2v_2'+m_3v_3'+...

The problem relates the story of Batman (m1=100kg) who is initially assumed at rest and lands on a boat with mass m2=580 kg initially moving at 14 m/s to the positive reference. When the collision takes place, both masses join and a common speed v_b is achieved by the common mass. Applying the conservation of momentum, we have

m_1v_1+m_2v_2=(m_1+m_2)v_b

Since v_1=0

m_2v_2=(m_1+m_2)v_b

Solving for v_b

\displaystyle v_b=\frac{m_2v_2}{m_1+m_2}

\displaystyle v_b=\frac{(580)(14)}{100+580}

\boxed{v_b=11.94\ m/s}

7 0
3 years ago
If ∠WXZ≅∠YXZ and WZ = 38, what is YZ?
Katyanochek1 [597]
<h3>Answer:  38</h3>

=================================================

Explanation:

The square markers tell us that we have right angles (aka 90 degree angles) at angle XYZ and XWZ. They are congruent by definition.

Another pair of congruent angles is WXZ and YXZ which are the left-most angles of each triangle.

The sides XZ and XZ are congruent to each other (reflexive property)

Based on those three previous paragraphs, we can use the Angle Angle Side (AAS) congruence theorem to prove that the triangles are congruent.

Specifically we could write \triangle XYZ \cong \triangle XWZ. The order of the letters is important so we know which letters pair up (eg: Y and W pair up as the 90 degree angles).

--------------------------------------

In short, the triangles are identical copies of each other. The upper triangle reflects over the line XZ to get the lower triangle, and vice versa. This means the smaller corresponding pieces must also be the same.

In this case, WZ = YZ = 38

3 0
2 years ago
20 POINTS
USPshnik [31]

Answer:

a) Only the first one is an identity.

Step-by-step explanation:

1). 8 cos O tan O csc O = 8   simplifies to:

cos O tan O csc O = 1

cos O * (sin O / cos O) * (1 /sin O)

=  cos O sin O / cos O sin O

= 1

So it is identity.

2) 13 sec^2 O/ cos^2 O - tan^2 O / cos^2O

= 13 sec^2 O - tan^2 O / cos^2 O

Now  sec^2 O = 1 + tan^2 O, so we have:

(13( 1 + tan^2 O) - tan^2 O) / cos^2 O

= (12 tan^2 O + 13) / cos^2 O

This is not always = 2 so its not an identity.

4 0
3 years ago
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