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3 years ago

Eighth grade

Mathematics

1 answer:

Ymorist [56]3 years ago

7 0

Answer:

b = 1

Step-by-step explanation:

Given the equation is:

- 5b + 2b - (-b) + 7 = 5

We separate the terms of b and the constants. To do that we subtract 7 from both the sides. We get:

- 5b + 2b - (-b) + 7 - 7 = 5 - 7

⇒ - 5b + 2b - (-b) = - 2

Now, simplifying the terms with 'b'.

⇒ -5b + 2b + b = - 2

⇒ (-5 + 2 + 1)b = - 2

⇒ -2b = -2

Dividing both the sides by -2, we get:

b = 1 which is the required answer.

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how many outfits of shoes does a female have for school if she has the choice of 2 pairs of shoes, 4 skirts, and 5 tops in her w

frez [133]

Answer:

if you are asking for a math equation then 2+4+5=11

Step-by-step explanation:

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4 years ago

Find the values of x and y. lines that appear to be tangent are tangent

Ket [755]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of $y = 122^o$

The value of $x = 61^o$

Step-by-step explanation:

Generally the total angle that make up a circle is

$\theta _T = 360$

From the diagram we see that

$\theta _T = y^o + 238^o$

=> $y^o = 360 -238$

$y^o = 122^o$

Generally angle that is formed as a result of interception of a chord and a tangent is equal to the intercepted arc divided by 2

This implies that

$x = \frac{y}{2}$

substituting values

$x = \frac{122}{2}$

$x = 61^o$

4 0

3 years ago

Find the measure of the angle, round to the nearest tenth: Sin X = .7547

dimulka [17.4K]

SIN(x) = .7547
X = INVERSE-SIN(.7547)
X = 49.0 degrees

4 0

3 years ago

There are two non congruent triangles where B=55 degrees a=15 and b=13. Find the measures of the angles of the triangle with the

liq [111]

Answer:

The side c needs to be 12.85 for the triangle to have greatest perimeter

Step-by-step explanation:

We are given;

b = 13

a = 15

Angle at b: B = 55°

Let's find side c.

Using the law of cosines,we have;

b² = a² + c² - 2ac•cos(B)

13² = 15² + c² - 2•15•c•cos(55)

169 = 225 + c² - 30c•cos(55)

c² - 30c•cos(55) + 225 - 169 = 0

c² - 30c•cos(55) + 56 = 0

c² - 30c•(0.5736) + 56 = 0

c² - 17.208c + 56 = 0

Using quadratic formula;

c = [-(-17.208) ± √((-17.208)² - (4•1•56)]/2(1)

c = [17.208 ± √(296.115 - 224)]/2

c = 8.604 ± 4.246

To have the greater perimeter, we need the larger value of c, thus we will use the positive sign and ignore the negative one ;

Thus,

c = 8.604 + 4.246 = 12.85

5 0

3 years ago

two runners start 30kilometer apart and run toward each other. they meet after 3hours. One Runner runs 2 kilometers per hour fas

belka [17]

Let the slower runners speed be X kilometers per hour.

Then the faster runners speed would be X+2 kilometers per hour.

The formula for distance is Speed times time.

The distance is given as 30 kilometers and time is given as 3 hours.

Since there are two runners you need to add the both of them together.

The equation becomes 30 = 3x + 3(x+2)

Now solve for x:

30 = 3x + 3(x+2)

Simplify:

30 = 3x + 3x +6

30 = 6x + 6

Subtract 6 from each side:

24 = 6x

Divide both sides by 6:

x = 24/6

x = 4

The slower runner ran at 4 kilometers per hour.

The faster runner ran at 4+2 = 6 kilometers per hour.

3 0

3 years ago