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Sedbober [7]
3 years ago
9

Is this a good drawing??

Mathematics
2 answers:
polet [3.4K]3 years ago
5 0
I doesn’t matter how bad the drawing it always good to me
Alexxandr [17]3 years ago
3 0

Answer:

I dont see a drawing???

Step-by-step explanation:

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This is a little cunfusing lol
Luba_88 [7]

Answer: its C

Step-by-step explanation: cause i did that already

5 0
3 years ago
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Help with this question plz thx
In-s [12.5K]
I think the answer is C
8 0
3 years ago
16. Find the domain of<br><br> x^2 + 5x + 4 / x^2 + 7x + 6
seropon [69]

Answer:

what is 52437 rounded to the bearest hundred

7 0
3 years ago
The diagonals of quadrilateral ABCD intersect at E (2,5). ABCD has vertices at A (3,7) and B (3,6). What must be the coordinates
Ivahew [28]

Answer:

C(1,3) and D(1,4).

Step-by-step explanation:

The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of  this quadrilateral ABCD intersect at E (2,5).

Recall that, the diagonals of a parallelogram bisects each other.

This means that; E(2,5) is the midpoint of each diagonal.

Let C and D have coordinates C(m,n) and D(s,t)

Using the midpoint rule:

(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})

The midpoint of AC is (\frac{m+3}{2}, \frac{n+7}{2})=(2,5)

This implies that;

(\frac{m+3}{2}=2, \frac{n+7}{2}=5)

(m+3=4, n+7=10)

(m=4-3, n=10-7)

(m=1, n=3)

The midpoint of BD is (\frac{m+3}{2}, \frac{n+7}{2})=(2,5)

This implies that;

(\frac{s+3}{2}=2, \frac{t+6}{2}=5)

(s+3=4, t+6=10)

(s=4-3, t=10-6)

(s=1, t=4)

Therefore the coordinates of C are (1,3) and D(1,4).

6 0
4 years ago
Name three decimals between 16.4 and 16.5. Draw a number line estimating the placement off all five decimals.
Doss [256]
16.42 and 16.43 and 16.44 It ranges from any numbers between 16.40-16.50

Remember that there is an imaginary 0 next to the tenths place.
7 0
3 years ago
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