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KonstantinChe [14]
2 years ago
5

Please show step by step

Mathematics
1 answer:
spayn [35]2 years ago
3 0

Answer:

15th term of the sequence is 36

Step-by-step explanation:

Given in the question,

a₁ = First term = -20

d = common difference = 4

Expression for the nth term of an arithmetic sequence is,

T_n=a_1+(n-1)d

Here, n = number or term

We have to calculate 15th term of the sequence,

T_{15}=-20+(15-1)(4)

     = -20 + 56

     = 36

Therefore, 15th term of the sequence is 36.

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Solve for x.<br> 2x² +21x-61 = (x+7)²<br><br> Please
Ymorist [56]

Answer:

x = \frac{-7 +\sqrt{489} }{2}

x = \frac{-7 - \sqrt{489} }{2}

Step-by-step explanation:

2x² +21x-61 = (x+7)²

expand

2x² + 21x - 61 = x² + 14x +49

move everything to one side

x² + 7x - 12 = 0

use quadratic formula

x = \frac{-b +- \sqrt{b^{2}-4ac } }{2a}

plug in the values

x = \frac{-7 +- \sqrt{7^{2}-4(1)(-110) } }{2(1)}

solve

x = \frac{-7 +- \sqrt{49-4(1)(-110) } }{2}

x = \frac{-7 +- \sqrt{49 + 440 } }{2}

x = \frac{-7 +- \sqrt{489} }{2}

7 0
2 years ago
Read 2 more answers
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