1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
3 years ago
6

City A had a population of 10000 in the year 1990. City A’s population grows at a constant rate of 3% per year. City B has a pop

ulation that is growing exponentially. In the year 2000, there were half as many people in B as in A. In the year 2010, the population of A was 20% more than the population of B.
When will the populations be equal? Give your answer in years after 1990.
Mathematics
1 answer:
Georgia [21]3 years ago
7 0

Answer:

City A and city B will have equal population 25years after 1990

Step-by-step explanation:

Given

Let

t \to years after 1990

A_t \to population function of city A

B_t \to population function of city B

<u>City A</u>

A_0 = 10000 ---- initial population (1990)

r_A =3\% --- rate

<u>City B</u>

B_{10} = \frac{1}{2} * A_{10} ----- t = 10 in 2000

A_{20} = B_{20} * (1 + 20\%) ---- t = 20 in 2010

Required

When they will have the same population

Both functions follow exponential function.

So, we have:

A_t = A_0 * (1 + r_A)^t

B_t = B_0 * (1 + r_B)^t

Calculate the population of city A in 2000 (t = 10)

A_t = A_0 * (1 + r_A)^t

A_{10} = 10000 * (1 + 3\%)^{10}

A_{10} = 10000 * (1 + 0.03)^{10}

A_{10} = 10000 * (1.03)^{10}

A_{10} = 13439.16

Calculate the population of city A in 2010 (t = 20)

A_t = A_0 * (1 + r_A)^t

A_{20} = 10000 * (1 + 3\%)^{20}

A_{20} = 10000 * (1 + 0.03)^{20}

A_{20} = 10000 * (1.03)^{20}

A_{20} = 18061.11

From the question, we have:

B_{10} = \frac{1}{2} * A_{10}  and  A_{20} = B_{20} * (1 + 20\%)

B_{10} = \frac{1}{2} * A_{10}

B_{10} = \frac{1}{2} * 13439.16

B_{10} = 6719.58

A_{20} = B_{20} * (1 + 20\%)

18061.11 = B_{20} * (1 + 20\%)

18061.11 = B_{20} * (1 + 0.20)

18061.11 = B_{20} * (1.20)

Solve for B20

B_{20} = \frac{18061.11}{1.20}

B_{20} = 15050.93

B_{10} = 6719.58 and B_{20} = 15050.93 can be used to determine the function of city B

B_t = B_0 * (1 + r_B)^t

For: B_{10} = 6719.58

We have:

B_{10} = B_0 * (1 + r_B)^{10}

B_0 * (1 + r_B)^{10} = 6719.58

For: B_{20} = 15050.93

We have:

B_{20} = B_0 * (1 + r_B)^{20}

B_0 * (1 + r_B)^{20} = 15050.93

Divide B_0 * (1 + r_B)^{20} = 15050.93 by B_0 * (1 + r_B)^{10} = 6719.58

\frac{B_0 * (1 + r_B)^{20}}{B_0 * (1 + r_B)^{10}} = \frac{15050.93}{6719.58}

\frac{(1 + r_B)^{20}}{(1 + r_B)^{10}} = 2.2399

Apply law of indices

(1 + r_B)^{20-10} = 2.2399

(1 + r_B)^{10} = 2.2399 --- (1)

Take 10th root of both sides

1 + r_B = \sqrt[10]{2.2399}

1 + r_B = 1.08

Subtract 1 from both sides

r_B = 0.08

To calculate B_0, we have:

B_0 * (1 + r_B)^{10} = 6719.58

Recall that: (1 + r_B)^{10} = 2.2399

So:

B_0 * 2.2399 = 6719.58

B_0  = \frac{6719.58}{2.2399}

B_0  = 3000

Hence:

B_t = B_0 * (1 + r_B)^t

B_t = 3000 * (1 + 0.08)^t

B_t = 3000 * (1.08)^t

The question requires that we solve for t when:

A_t = B_t

Where:

A_t = A_0 * (1 + r_A)^t

A_t = 10000 * (1 + 3\%)^t

A_t = 10000 * (1 + 0.03)^t

A_t = 10000 * (1.03)^t

and

B_t = 3000 * (1.08)^t

A_t = B_t becomes

10000 * (1.03)^t = 3000 * (1.08)^t

Divide both sides by 10000

(1.03)^t = 0.3 * (1.08)^t

Divide both sides by (1.08)^t

(\frac{1.03}{1.08})^t = 0.3

(0.9537)^t = 0.3

Take natural logarithm of both sides

\ln(0.9537)^t = \ln(0.3)

Rewrite as:

t\cdot\ln(0.9537) = \ln(0.3)

Solve for t

t = \frac{\ln(0.3)}{ln(0.9537)}

t = 25.397

Approximate

t = 25

You might be interested in
Help guys pls asap!!!
saveliy_v [14]
2 sorry if i’m wrong
7 0
2 years ago
Read 2 more answers
Choose the equation that represents a line that passes through points (-3,2) and (2,1)
yawa3891 [41]

Answer:

y = -0.2x + 1.4

Step-by-step explanation:

I graphed the points on the graph below. Then I found the slope of the line.

If this answer is correct, please make me Brainliest!

6 0
3 years ago
Please help I need this
Lubov Fominskaja [6]

Answer:

from side a _2,4.5

from side b _-4

5,-2.

hope this will be helpful for you.

8 0
3 years ago
In a bag, there are 5 red marbles, 2 blue marbles, and 3 purple marbles. What is the probability of drawing a purple marble?
Kitty [74]

Answer:

3/10 or 30%

Step-by-step explanation:

Add all of the marbles: 5+2+3=10

Then use a fraction to represent the three purple marbles: 3/10

That porportion is your answer

7 0
2 years ago
What’s 53/3 simplified
aleksley [76]

Answer:

<em>53/3 simplified is 17 2/3</em>

3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the measure of
    5·1 answer
  • Write a first step question and answer.Then solve the problem.The store owner gets a shipment of 7 boxes of games.There are 6 ga
    10·2 answers
  • NEED HELP PLEASEE I AM BEGGING YOU PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    10·1 answer
  • Prime factorization of 1050
    12·1 answer
  • Help! Using complete sentences, explain how to find the maximum value for each function and determine which function has the lar
    8·1 answer
  • -2 degree drop in temp every 1,000 ft airplane climbs in the sky. Temp on ground is 57 degrees. What is temperature when plane r
    7·1 answer
  • Fill in the blank to complete the identity.
    7·1 answer
  • In ΔDEF, EF = 15, FD = 13, and DE = 4. Which list has the angles of ΔDEF in order from smallest to largest?
    14·1 answer
  • Tile the rectangle shown using square inches to find the area, and then use multiplication to confirm the area. Use paper to sho
    10·1 answer
  • Are all congruent rectangles similar?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!