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Semenov [28]
3 years ago
9

Which method is valid for proving that two circles are similar?

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

'a',  'c', and  'd'  are true for any two circles.  That's because
ALL circles are similar.  You don't need to prove it.  The question
is weird.


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Are these three side lengths a right triangle?<br> 5, 5, 5√s<br> yes or no?
11111nata11111 [884]

Answer:

no

Step-by-step explanation:

5 0
3 years ago
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Solve for k: -3k -3k = -29 + 77
sineoko [7]

Answer:

k=48

Step-by-step explanation:

Add  -29 and 77

k: -3k -3k =48

6 0
3 years ago
Read 2 more answers
Determine the solution set of each equation
maks197457 [2]

A=x1 = -8,x2 =2, B=x1= -5,x2=5, C=y1 = -4, y2 =5, D=y 18 over 5

alternative form

y=3 3over 5, =3.6

And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

x2 +8x-2x-16=0

factor out x for the expression

xx(x+8)-2x-16=0

factor out -2 from the expression

xx(x+8)- 2(x+8)=0

factor out x+8 from the expression

(x+8)x(x- 2)=0

when the product of factors equals 0,at least one factor is 0

x+8=0

x - 2=0

solve the equation for x

x= -8

x - 2=0

solve the equation for x

x= -8

x =2

the equation has 2 solution

x1 = -8,X2 =2

answer is

x1 = -8,x2 =2

Or

Solving steps:Number of solution

x²+6x-16=0

Determine the number of solution using the

discriminant D =b²- 4ac

D =6²- 4x1x(-16)

simply the expression

D=100

Since D>0, the quadratic equation has 2 real solution

2 real solution

Answer is

2 real solution

Question B

Solving steps:Solve the quadratic equation

x²-25=0

Move the constant to the right-hand side and change its sign

x²=25

Take the square root of both sides of the equation and remember to use both positive and negative roots

x=+5

Write the solutions,one with a +sign and one with a -sign

x= -5

x=5

The equation has 2 solutions

x1= -5,x2=5

the answer is

x1= -5,x2=5

Or

Solving steps:Number of solution

x²-25=0

Determine the number of solutions using the discriminant D=b²- 4ac

D=0²- 4x1x(-25)

Simply the expression

D=100

Since D>0,the quadratic equation has 2real solutions

Answer is

2real solutions

answer of question C is

y1 = -4, y2 =5

Answer of question D is

y 18 over 5

alternative form

y=3 3over 5, =3.6

Answer of question E is

x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667

Please mark as brainiest

3 0
3 years ago
Read 2 more answers
Calculate the value of x in the equation 2x - 15 =5 - 3×
pshichka [43]

\bold{2x - 15 = 5 - 3x} \\  \bold{2x + 3x = 15  +  5} \\  \bold{5x =20 } \\  \bold{x =  \cancel{ \frac {20}{5} }} \\  \bold{x = 4}

Hope it helps

3 0
1 year ago
Read 2 more answers
If EG = 3y - 10 and ET = 2y, find the value of y In parallelogram FGHI.<br> 1<br> Find Value of y.
Ksenya-84 [330]
<h3>Answer:  y = 10</h3>

=====================================

Work Shown:

EI = EG

3y-10 = 2y

3y-10-2y = 0

y-10 = 0

y = 0+10

y = 10

Note how if y = 10, then

  • EI = 3y-10 = 3*10-10 = 20
  • EG = 2y = 2*10 = 20

Both EI and EG are 20 units long when y = 10. This confirms the answer.

6 0
3 years ago
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