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3 years ago

HELP PLEASE!!!!

1 answer:

4 0

To find her take home pay, you subtract her deductions from her gross pay and then divide her take-home pay by her gross pay and then multiply by 100%.
So,
Take-home pay = 2644-548.30=2095.70 Percent = (2095.70/2644)*100%=79.262%
So your answer is B)79%
Hope this helps :)
If you need anymore help with questions then feel free to ask me :D

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Plz, help. What is the mode?

Ronch [10]

Answer:

None

Step-by-step explanation:

Mode is the number that repeats the most. All of these numbers are unique, and there is no repeats, therefore there is no mode.

5 0

3 years ago

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Which of the following scenarios demonstrates an exponential decay? A. A tennis tournament in which after each round, half the p

Sliva [168]

Answer:

A. A tennis tournament in which after each round, half the players are eliminated.

Step-by-step explanation:

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3 years ago

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G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

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3 years ago

can someone please help me with question 1? I will give brainliest to first answer! Thank you so much! I really appreciate anyon

Goryan [66]

Answer:

49 in the first box and 7 in the second one

25 in the 3rd box and 5 in the 4th

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3 years ago

In ΔTUV, v = 990 inches, t = 840 inches and ∠U=148°. Find the length of u, to the nearest inch.

Scilla [17]

Answer:

the answer is 1760

Step-by-step explanation:

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3 years ago