Answer:
It would be B
Step-by-step explanation:
Hope this helps.
X=y-7
x=2-8y
both equal x so
subsitute y-7 for x in other equaton
y-7=2-8y
add 8y
9y-7=2
add 7
9y=9
divide 9
y=1
sub back
x=y-7
x=1-7
x=-6
(x,y)
(-6,1)
Answer:
Step-by-step explanation:
The easiest way to think about increasing area is by taking a square, if you double the dimensions, let's say they were 1 by 1 and then was made into a 2x2 square, you can fit four of the original cube (1x1) into the 2x2. So when the dimensions are doubled the area is quadrupled.
Even easier shortcut:
Take the cube idea, when the dimensions are messed with for anything, (works for volume too) always think of the smaller piece as 1x1 or 1x1x1. Then if the dimensions are double make it 2x2 or 2x2x2. If the dimensions are tripled then do 3x3 or 3x3x3, etc... 1x1=1x1x1, they are both equal to 1. So think of that as the numerator. the 2x2 in this case is equal to 4 so the smaller piece is 1/4 of the bigger one. Shown with volume if you double the dimensions of a cube that was 1x1x1 into 2x2x2. 1x1x1 still equals 1 so that's still the numerator and 2x2x2 is equal to 8 so the 1x1x1 cube is 1/8 of the 2x2x2, in other words you can fit eight 1x1x1 cubes into the 2x2x2 cube.
Hope this helps with area and volume.
A)A cylinder with height 4 inches and radius 4 inches.
Step-by-step explanation:
Volume of a Cylinder = \pi r^2 h
Next, we determine the volume of the options being considered by Tommy.
Option A:
A cylinder with height 4 inches and radius 4 inches.
Volume =\pi *4^2*4=64\pi cubic inches
Option B
A cylinder with height 7 inches and diameter 4 inches.
Volume =\pi *2^2*7=28\pi cubic inches
Option C
A cylinder with height 5.5 inches and radius 3 inches.
Volume =\pi *3^2*5.5=49.5\pi cubic inches
Option D
A cylinder with height 6.5 inches and Base Area B = 4 pi inches squared.
Volume =4*6.5*\pi=26 \pi cubic inches
The cylinders in Option A will hold more soup than the other two cans Tommy is considering.
