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Elden [556K]
3 years ago
14

Wilson and his family ate dinner at a restaurant. Their bill before tax came to $71.How much did dinner cost Wilson if he used a

coupon for 10% off and a tax of 9% was charged after the coupon was applied? (to the nearest hundredth)
Mathematics
2 answers:
Sonja [21]3 years ago
7 0

Answer:

he paid 69.65$

Step-by-step explanation:

morpeh [17]3 years ago
6 0

$69.65

71-10%=63.9

63.9+9%= 69.651

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6 -they lost that many


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666







6 0
3 years ago
7 dollars is equivalent to what in dimes
Stels [109]

Answer: 70

Step-by-step explanation: 10 dimes = a dollar

10 x 7 = 70 dimes

4 0
2 years ago
Read 2 more answers
How much money is a $210 increased by 40%
KengaRu [80]
When you increase something by 40%, multiply the something by 1.4

210*1.4=294

The answer is $294

Hope this helps!
8 0
3 years ago
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a citrus grower ships grapefruit in boxes of 10. one season the grower shipped 20,400 boxes of grapefruit. how many grapefruit w
MatroZZZ [7]

10 grapefruit in each box. If the grower shipped 20,400 boxes. You would have to multiply to find out the total number of grapefruit.

20,400 boxes times 10 in each box.

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Hope this helps. :)

7 0
3 years ago
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According to the Environmental Protection Agency, the mean miles per gallon of all large cars manufactured in 2012 driven under
Whitepunk [10]
Step 1: Writing Null and Alternate Hypothesis

First we need to write the Null and Alternate Hypothesis for this problem.

Researcher claims that mileage will be increased on addition of Fuel additive. So the null and alternate hypothesis will be:

H_{o}: μ ≤ 25.1        (Null Hypothesis)
H_{a}: μ > 25.1        (Alternate Hypothesis)

This is a Right Tailed Test. Since population standard deviation is not know, we will use t-test to check the researchers claim.

Step 2: Finding Test Statistic

Sample Mean = x = 26.8
Standard Deviation = s = 3.9
Sample Size = n = 35 
Degrees of Freedom = df = n - 1 = 34

Test statistic(t) is given by:

t= \frac{x-u}{ \frac{s}{ \sqrt{n} } } \\  \\ 
t= \frac{26.8-25.1}{ \frac{3.9}{ \sqrt{35} } } \\  \\ 
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Step 3: Finding p value

Using t table or calculators find the p value for t=2.579 with 34 degrees of freedom for one tailed test.

P value comes out to be:
p = 0.0072

Step 4: Conclusion

Since the p value is lesser than the significance level of 0.05, we reject the Null Hypothesis.

We have enough evidence to support the researcher's claim that the new additive increases the miles per gallon of the cars. 
8 0
3 years ago
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