First you can apply the a²-b² = (a+b)(a-b) theorem, you'll get:
(p²)² - 9² = (p²+9)(p²-9), but that's not all, you can apply it again on the last factor:
(p²+9)(p²-3²) = (p²+9)(p+3)(p-3)
The first factor cannot be simplified like that, so that's the furthest factorization. So answer (3) is the right one.
Answer:
f=x-9
Step-by-step explanation:
Answer:
I assume you're joking.
Step-by-step explanation:
I think that
A=0
B=0
C=0
D=0
Hope this helped.
Answer:
x = 6, x = -5, x = 9
if f(x)=(x-6)(x+5)(x-9)
Step-by-step explanation:
The zeros of a polynomial in factored form can be found by setting the polynomial equal to zero and then realizing if a product is zero, then at least one of it's factors is zero.
So we have the zero's are the x's that satisfy
(x-6)(x+5)(x-9)=0.
We just need to solve three equations:
x-6=0
This can be solved by adding 6 on both sides: x=6
x+5=0
This can be solved by subtracting 5 on both sides: x=-5
x-9=0
This can be solved by adding 9 on both sides: x=9
The solutions are in { 6,-5,9 }.
1. A (x²-4y)³
2. ?=5
3. (x+3)(3y-5)
4. (4y+7)(5x-1)
