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Andrews [41]
3 years ago
10

A(9b+13) in expanded form

Mathematics
2 answers:
NemiM [27]3 years ago
5 0

Answer:

I'm so sorry, I don't know it.

Scilla [17]3 years ago
3 0
(A•9B)+(A•13) hope this helps
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Please please <br> I need help ((((riiiight now)))<br> What's the right answer and explain why!!!!!
Ilia_Sergeevich [38]
First you can apply the a²-b² = (a+b)(a-b) theorem, you'll get:

(p²)² - 9² = (p²+9)(p²-9), but that's not all, you can apply it again on the last factor:

(p²+9)(p²-3²) = (p²+9)(p+3)(p-3)

The first factor cannot be simplified like that, so that's the furthest factorization. So answer (3) is the right one.
5 0
3 years ago
Read 2 more answers
Pls help me i’ll do anything and hurry time limit. f(x) = 9 - x. evaluate f(-1)
aleksklad [387]

Answer:

f=x-9

Step-by-step explanation:

3 0
3 years ago
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Prove that (AxB).(BxC)+(BxC).(AxD)+(CxA).(BxD)=0
shepuryov [24]

Answer:

I assume you're joking.

Step-by-step explanation:

I think that

A=0

B=0

C=0

D=0

Hope this helped.

8 0
3 years ago
Read 2 more answers
The polynomial f(x) is written in factored form:
qaws [65]

Answer:

x = 6, x = -5, x = 9

if f(x)=(x-6)(x+5)(x-9)

Step-by-step explanation:

The zeros of a polynomial in factored form can be found by setting the polynomial equal to zero and then realizing if a product is zero, then at least one of it's factors is zero.

So we have the zero's are the x's that satisfy

(x-6)(x+5)(x-9)=0.

We just need to solve three equations:

x-6=0

           This can be solved by adding 6 on both sides:  x=6

x+5=0

         This can be solved by subtracting 5 on both sides: x=-5

x-9=0

         This can be solved by adding 9 on both sides: x=9

The solutions are in { 6,-5,9 }.

7 0
4 years ago
Read 2 more answers
1. Which expression is the completely factored form of x^6−64y^3 ?
GalinKa [24]
1. A (x²-4y)³
2. ?=5
3. (x+3)(3y-5)
4. (4y+7)(5x-1)
5 0
3 years ago
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