Question

Solve the equation sin^2x=3Cos^2X. I would love to graduate...so thanks in advance!

Answer 1

Answer:

240°

Step-by-step explanation:

$sin^2x=3cos^2x \\ \\ sin^2x=3(1 - sin^2x )\\ \\ sin^2x=3 - 3sin^2x \\ \\ sin^2x + 3sin^2x=3 \\ \\ 4sin^2x=3 \\ \\ sin^2x= \frac{3}{4} \\ \\ sinx= \sqrt{ \frac{3}{4} } \\ \\ sinx= \frac{ \sqrt{3} }{2} \\ \\ sinx= sin \: 60 \degree \\ \\ in \: the \: second \: quadrant \\ sinx= sin \: (180 \degree - 60 \degree ) = sin \: 120 \degree \\ \\ in \: the \: third \: quadrant \\ sin x= sin \: (180 \degree + 60) \degree = sin \: 240 \degree$