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KengaRu [80]
3 years ago
6

Plz guys help i need asap its part b im stuck

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

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IgorC [24]

Answer:

  • B=42°
  • C=98°
  • c=10.7 units

Step-by-step explanation:

Given

  • Angle A = Ф = 40°
  • a=8
  • b=7

We know that trigonometric ratio as

  • sin Ф = opposite/hypotenuse
  • cos Ф = adjacent/hypotenuse
  • tan Ф = opposite/adjacent

as

sin A = sin 40 = opposite/hypotenuse

From the diagram, it is clear that the opposite of angle A is a=8 and the hypotenuse is 'c'.

also the angle

sin A = sin 40 = opposite/hypotenuse = a/c = 8/c

sin 40 = 8/c

c = 8/sin 40

c = 8/0.745

c = 10.7

so the value of c will be: 10.7 units

so

tan B = opposite/adjacent

         = b/a

         = 0.9

B=\tan ^{-1}\left(0.9\right)

   =42^{\circ \:}

Therefore, the value of B = 42^{\circ \:}

As the sum of the angles of triangle ABC is 180.

i.e.

A+B+C = 180

(40)° + (42)° + C = 180°

C = 180° - 40° - 42°

  = 98°

Therefore, the value of C = 98°

Hence,

  • B=42°
  • C=98°
  • c=10.7 units
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Sholpan [36]
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  sin(58°) = BC/(14 cm)

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