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KengaRu [80]
3 years ago
6

Plz guys help i need asap its part b im stuck

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

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3 years ago
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Answer:

\sqrt[]{\frac{x+8}{4}}-3

Step-by-step explanation:

g(x)=4(x+3)^2-8

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Now swap y and x

x=4(y+3)^2-8

Add 8 on both sides.

x+8=4(y+3)^2-8+8

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Extract the square root on both sides.

\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}

\sqrt[]{\frac{x+8}{4}}=y+3

Subtract 3 on both sides.

\sqrt[]{\frac{x+8}{4}}-3=y+3-3

\sqrt[]{\frac{x+8}{4}}-3=y

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