Answer:
512 student tickets.
Step-by-step explanation:
Let x be number of student tickets and y be number of adult tickets.
We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:
We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:
From equation (1) we will get,
Substituting this value in equation (2) we will get,
Therefore, 512 student tickets were purchased at Fridays football game.
Answer:
i think its a trick question
Step-by-step explanation:
theres no way theres a righr answer the 20$ on is always ahead
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
S = 32 and t = 45
You replace the letters into numbers...
Since (st) is the same thing as (s × t), it would be 32 × 45, which equals to 1,440.
Then replace the r with 5, so now it's (6 × 5), instead of (6r).
st ÷ (6r) → 1,440 ÷ 30 = 48
Value of st ÷ (6r) = 48
