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Mars2501 [29]
3 years ago
11

I need help with problem.

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

The measure of DC is 20ft.

Step-by-step explanation:

Because the problem states that BA=AC, AD becomes the bisector of angle BAC. This means that BD and DC must be the same length.

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What is the 117th term in the sequence 1,5,9,13,...
Ivahew [28]

Answer:

the 117th number value is-->582

7 0
3 years ago
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Gabrielle is traveling to Mexico and needs to exchange $440 into Mexican pesos. If each dollar is worth 11.84 pesos, how many pe
alexira [117]

Answer:

5209.60 pesos

Step-by-step explanation:

$440 x 11.84= 5209.60

6 0
3 years ago
A cone with a radius 2 units is shown below. Its volume is 29 cubic units. Find the height of the cone
rusak2 [61]

Answer:

The height of the cone is 6.9\ units

Step-by-step explanation:

we know that

The volume of the cone is equal to

V=\frac{1}{3}Bh

where

B is the area of the circular base of the cone

h is the height of the cone

In this problem we have

V=29\ units^{3}

r=2\ units

<em>Find the area of the base B</em>

B=\pi r^{2}

substitute the value of r

B=\pi (2)^{2}=4 \pi\ units^{2}

<em>Find the height of the cone</em>

29=\frac{1}{3}(4 \pi)h

h=29*3/(4 \pi)

assume \pi=3.14

h=29*3/(4*3.14)=6.9\ units

7 0
3 years ago
A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each select
Digiron [165]

Answer:

B. \frac{24}{121}.

Step-by-step explanation:

Total number of marbles = 11.

Since, after choosing the first marble, we are putting it back and then the second marble is chosen.

As, there are 4 shaded marbles.

So, the probability of getting the first marble shaded = \frac{\binom{4}{1}}{\binom{11}{1}} = \frac{4}{11}

Also, there are 6 odd labeled marbles.

So, the probability of getting the second marble being odd labeled = \frac{\binom{6}{1}}{\binom{11}{1}} = \frac{6}{11}

So, the probability of getting the first marble shaded and second marble labeled odd = \frac{4}{11}\times \frac{6}{11} = \frac{24}{121}.

Hence, the required probability is \frac{24}{121}.

4 0
3 years ago
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There are (53)2 ⋅ 50 hens in a bird enclosure. What is the total number of hens in the enclosure? (1 point)
Margaret [11]

Answer:

<u>The correct answer is C. 5⁶</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of hens in a bird enclosure = (5³)² * 5⁰

2. What is the total number of hens in the enclosure?

Let's recall a couple of properties of the exponents:

1. When you raise any number to a zero power you'll always get 1, with the exception of zero itself.

x⁰ = 1, x ≠ 0

2. The power of a power property says that to calculate a power of a power you just have to multiply the exponents, this way:

(x⁴)⁵ = x ⁴°⁵ = x²⁰

Now, applying those two properties, we have:

(5³)² * 5⁰ = 5³°² * 1 = 5⁶

<u>The correct answer is C. 5⁶</u>

3 0
3 years ago
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