Work:
2x+5(6x+23)=-13
2x+30x+115=-13
32x=-128
x=-4
y=6(-4)+23
y=-24+23
y=-1
The answer is (-4,-1)
Hopefully this helps!
Answer: c
<u>Step-by-step explanation:</u>
When multiplying matrices, multiply ACROSS with the left matrix and DOWN with the right matrix.
![\text{Example}:\left[\begin{array}{cc}a&b\\c&d\end{array}\right] \times \left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}ax+by\\cx+dy\\\end{array}\right]](https://tex.z-dn.net/?f=%5Ctext%7BExample%7D%3A%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dax%2Bby%5C%5Ccx%2Bdy%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}5&2\\3&-1\end{array}\right] \times \left[\begin{array}{c}2\\3\end{array}\right] =\left[\begin{array}{c}5(2)+2(3)\\3(2)-1(3)\\\end{array}\right] = \left[\begin{array}{c}16\\3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%262%5C%5C3%26-1%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C3%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D5%282%29%2B2%283%29%5C%5C3%282%29-1%283%29%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D16%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
ANSWER

EXPLANATION
The constant difference of p values is
4-2=2
The constant difference of the 'q' values is
-28--14=-14
The function is of the form:

where


We plug in the values to get;

Expand:

Simplify:

Answer:
Graph 1
Step-by-step explanation:
The reason for the answer being graph one is because the equation |x| = 1 means the absolute value of x could either be 1 or -1 , resulting in points rather than lines as the equation is already solved rather then being less than or greater than.
Hope this helps!
The denominator would be is 2-1