Question

A wheel with radius 1 foot makes 1 revolution in 4 seconds. What is the linear velocity, in feet per second, of a point on the edge of the wheel? 4π 8π

Answer 1

Answer:

$v=\dfrac{\pi}{2}\ ft/s$

Step-by-step explanation:

Given that,

A wheel with radius 1 foot makes 1 revolution in 4 seconds

We need to find the linera velocity of a point on the edge of the wheel. We know that, the linear velcity is given by :

$v=r\omega$

Where

$\omega$ is angular velcocity,$\omega=2\pi\ rad$

$\omega=\dfrac{1}{4}\times 2\pi\\\\=0.5\pi\ rad/s$

So

$v=1\times 0.5\pi\\\\v=\dfrac{\pi}{2}\ ft/s$

So, the linear velocity of the wheel is equal to $\dfrac{\pi}{2}\ ft/s$.

Answer 2

Answer:

pi/2

B

Step-by-step explanation:

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