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Ugo [173]
3 years ago
12

I need this for homework plz help me.

Mathematics
2 answers:
lawyer [7]3 years ago
7 0
I’ll help you with your homework if after I answer your question for you can you pay me $5 for answering your question.
kodGreya [7K]3 years ago
5 0
Hello how are you :D
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Scilla [17]

Answer:

<em>y=</em><em>1</em><em>/</em><em>3</em><em> </em><em>would </em><em>be </em><em>the </em><em>correct</em><em> </em><em>answer</em><em> </em><em>as </em><em>long </em><em>as </em><em>the </em><em>x </em><em>is </em><em>not </em><em>only </em><em>attached</em><em> to</em><em> the</em><em> </em><em>three,</em><em> </em><em>but </em><em>1</em><em>/</em><em>3</em><em> </em><em>as </em><em>a </em><em>whole</em><em>.</em><em> </em><em>I </em><em>hope</em><em> </em><em>this </em><em>helps!</em>

6 0
2 years ago
Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D′E′F′G′H′I′:
dalvyx [7]

Answer:

A

Step-by-step explanation:

it goes down by 9 and left by 3

7 0
2 years ago
F(x) = 2/x, g(x) = |x| -1 <br><br><br> What is the domain of (fog) (x)?<br><br> will mark brainliest
brilliants [131]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

3 0
3 years ago
Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4
Viefleur [7K]

We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.


6 0
3 years ago
If B(x)=-1,then what is x​
jekas [21]

Step-by-step explanation:

6 0
3 years ago
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