Complete the table below to show the differences bettween algebraic expression and equation
1 answer:
Complete the table below to show the differences between algebraic
expression and equation.
Describe each to show their differences.
Give 3 examples of each.
Answer:
Explained below with examples
Step-by-step explanation:
1. Algebraic expression in mathematics are basically expressions that are formed from variables, integer constants, and also algebraic operations.
Examples include;
>> 2x² − xy
>> 3ab + 2b²
>> x² + y²
2. An algebraic equation is a phrase where the two sides of the equation which are the left and right hand sides are connected by the equal to sign (=).
Examples are;
>> 3y - y² = 2y² + 2
>> 3x - 4y = x + 2
>> 5a + 3b = 2b - 1
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Answer:
x = 45°
Step-by-step explanation:
We can tell that "x + 115" and 160° are vertically opposite angles, which means that they are equal. (Refer to image)
⇒ x + 115 = 160
⇒ x = 160 - 115
⇒ x = 45°
Learn more about vertically opposite angles: brainly.com/question/68367
<h3>Image:</h3>
Answer:
A), B) and D) are true
Step-by-step explanation:
A) We can prove it as follows:
B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then
.
C) Consider . This set is orthogonal because
, but S is not orthonormal because the norm of (0,2) is 2≠1.
D) Let A be an orthogonal matrix in . Then the columns of A form an orthonormal set. We have that
. To see this, note than the component
of the product
is the dot product of the i-th row of
and the jth row of
. But the i-th row of
is equal to the i-th column of
. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then
E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.
In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set and suppose that there are coefficients a_i such that
. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then
then
.