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kvasek [131]
3 years ago
11

WILL MARK BRAINLIEST IF UNDER 6 MINS FROM RSM! HELP! The difference between a and b is 12. The number a is 5 more than 3 times t

he number b. Which of the following pairs of equations could be used to find the values of a and b? (A) b−a=12 a=3b+5 (B) a−b=12 b=3a+5 (C) a/b =12 a=3b+4 (D) a−b=12 a=3b+5 (E) b−a=12 3b=a+5
Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

Choice D.  a - b = 12  and  a = 3b + 5

Step-by-step explanation:

so   |a - b| = 12  

a = 3b + 5

3b + 5 - b  = 12

2b + 5 = 12

b = 7/2

what if  b - a = 12

b - 3b - 5 = 12

-2b = 17

b < 0  no.

choice A. works  so does choice D.)

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c) P(x≤7)=0.8328

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a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

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We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

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b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55

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As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8

The probability of having between 4 and 8 customers choosing the oversize version is:

P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989

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