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Sever21 [200]
3 years ago
14

Please help, i seriously don't understand how to solve this ;_;

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

10

Step-by-step explanation:

thats correct i think

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240: 35,236,237,238,239,241,242,243,244
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Write the equation in standard form for the circle with center (0, -1) and radius 10.
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x^2 + (y+1)^2 = 10^2

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Centre (p,q) = (0, -1)

radius, r = 10

General Equation of a circle

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x^2 + (y+1)^2 = 10^2

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Which of the following data sets contain an outlier?
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4 years ago
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The answer is (x,y) —> (y,-x)
8 0
4 years ago
Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0
2 years ago
Read 2 more answers
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