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balandron [24]
3 years ago
7

Choose an appropriate unit of measurement for each quantity

Mathematics
1 answer:
tangare [24]3 years ago
4 0
下兩一習床我門木戈來登九儡剪水門錄口驗啊卜
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Factor the expression using GCF 7+14a
Lana71 [14]
The GCF of 7 and 14a is 7, so the factors are:-

    7(1 + 2a)
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Lara solved an equation incorrectly, as shown below:
son4ous [18]

We have been given the steps to solve the equation as

Step 1: 2x = 18

Step 2: x = 18 − 2

Step 3: x = 16

There is an error in step 2.

We have 2x=18

x is in multiplication with 2. So in order to get rid of 2 from the left hand side, we perform opposite operation of multiplication i.e. division.

So we must divide both sides by 2.

Therefore, A is the correct option.

A) She did not divide 18 by 2.

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What is the slope of the line that passes through the points (-4, 8) and (-14, 8) ?
jasenka [17]

Answer:

Step-by-step explanation:

(8-8)/(-14+4) = 0/-10 = 0 is the slope

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3 years ago
How much cellular data does Brainly.com use?
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3 years ago
Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
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