To determine the value of the given algebraic expression above, we simply substitute the values of each variable to the variables in the expression and evaluate the expression. We do as follows:
6x(y^2)(z)
when x = 0.5
y = -1
z = 2
6(0.5)((-1)^2)(2)
3(1)(2)
6
The value of the algebraic expression would be 6. An algebraic expression consists of variables which are represented with letters like for this case x, y and z, a coefficient which is indicated by numbers (e.g. 6 ) and exponents like 2 for the expression above. Often times expressions contains a number of terms which consists of those elements.
Answer:
m<V = 11.2 degrees
Step-by-step explanation:
In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.
From the triangle;
UV = hypotenuse = 6.2feet
WU = opposite = 1.2feet
Required
m<V
Using the SOH CAH TOA identity
sin m<V = opp/hyp
sin m<V = WU/UV
sin m<V = 1.2/6.2
sin m<V = 0.1936
m<V = arcsin(0.1936)
m<V = 11.16
m<V = 11.2 degrees ((to the nearest tenth of a degree)
Answer:
9 37/50
Step-by-step explanation:
I wrote it out and my math teacher told me
Answer:8 lunches
Step-by-step explanation: If you divide 2.50 from 20 you get 8. So it'll be 8 lunches.
Given:
The figure of a triangle DEF.
To find:
The coordinate of image of given triangle after reflection over y-axis.
Solution:
The vertices of given triangle are D(1,4), E(4,3), F(2,0).
If a figure is reflected over the y-axis, then the rule of reflection is
Using this rule, we get
Therefore, the coordinates of image are D'(-1,4), E'(-4,3) and F'(-2,0).
