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3 years ago

Please help! ASAP!!!!

Mathematics

1 answer:

larisa86 [58]3 years ago

7 0

Answer:

Part A) 2(n/6) - 9

Part B) the expression would change to 2(n/6) + 9 if it said 'more than'

Step-by-step explanation:

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I need help plz ASAP

netineya [11]

Answer: x=8

Step-by-step explanation:

the sum of the interior angles of a quadrilateral is 360 (number of sides-2 * 180)

$14x-7+11x-2+93+76= 360\\25x + 160=360\\25x= 200\\x=8$

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3 years ago

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Find the sum of 3b/b 2 and 12/b 2 and express it in simplest form

alexandr1967 [171]

$\frac{3b}{b^{2}} + \frac{12}{b^{2}} = \frac{3b + 12}{b^{2}} = \frac{3(b) + 3(4)}{b^{2}} = \frac{3(b + 4)}{b^{2}}$

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3 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

4 years ago

Pls help stuck on big ideas math

beks73 [17]

Answer:

x = 15

Step-by-step explanation:

Substitute: -4/5x + 7 = -5

Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7

Calculate the sum or difference: -4/5x = -12

Divide both sides of the equation by the coefficient of variable: x = -12 × (-5/4)

Remove the parentheses: x = 12 × 5/4

Cross out the common factor: x = 3 × 5

Calculate the product or quotient: x = 15

So the answer is: x = 15

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3 years ago

How much rice will each person have if 3 people shared 1/2 lb of rice equally

svet-max [94.6K]

1/2 = 3/6

Each person would have 1/6 of rice.

6 0

3 years ago

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