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Anna71 [15]
3 years ago
6

Please help! ASAP!!!!

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0

Answer:

Part A)  2(n/6) - 9

Part B)  the expression would change to 2(n/6) + 9 if  it said 'more than'

Step-by-step explanation:

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If a guy named josh got 45 bucks for his b-day and already had 237 bucks. How much money does josh have all together.
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That’s easy it is 282

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Richard wants to find out his current grade in math dass after taking five quizzes. Which measure of center
Salsk061 [2.6K]

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question does not seem complete, from what i know it sounds like he should add up the test scores and divide it by five, that will give him his average which should be his grade, please update question if possible

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3 years ago
Does anyone have answers for the Unit 6-Lesson 9: Rational Expressions and Functions Unit Test? I really need them, and will giv
GalinKa [24]

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on edge?

Step-by-step explanation:

5 0
3 years ago
Brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a mixture that is 60% c
algol [13]

The equation that can be used to find x, the amount of the 60% mixture used to create the 65% mixture is:

0.60*x + 0.80*(100 - x) = 0.65*(100).    

<h3>Which equation we should use?</h3>

First, let's define two variables:

  • x = pounds of the 60% copper brass.
  • y = pounds of the 80% copper brass.

We know that we want to make 100 lb of 65% copper brass, then we must have that:

x + y = 100

And the percentage of copper before and after mixing must be the same, so we can write:

0.60*x + 0.80*y = 0.65*(x + y).

(where the percentages are written in decimal form).

Then we have a system of equations:

x + y = 100

0.60*x + 0.80*y = 0.65*(x + y).

To get a single equation, we can isolate the variable "y" on the first equation:

y = 100 - x

Now we replace that in the other equation:

0.60*x + 0.80*(100 - x) = 0.65*(100).      

This is what we wanted to get, an equation that can be used to find x, the amount of the 60% mixture used to create the 65% mixture.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

4 0
2 years ago
Find the minimum and maximum possible areas of a rectangle measuring 6 km by 11 km.
ExtremeBDS [4]
Assuming your numbers are rounded to the nearest km, the minimum area will be ...
  (5.5 km)·(10.5 km) = 57.75 km² . . . minimum

And the maximum area will be ...
  (6.5 km)·(11.5 km) = 74.75 km² . . . maximum

_____
When a number is rounded to 6 km as the nearest km, its value may actually be anywhere in the range 6 km ± 0.5 km. If you really want to get technical about it, the ranges of possible dimensions are [5.5, 6.5) km and [10.5, 11.5) km, and the range of possible areas is [57.75, 74.75) km².
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3 years ago
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