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3 years ago

#4

Mathematics

1 answer:

Lapatulllka [165]3 years ago

3 0

Answer:

I dont understand!!!

Step-by-step explanation:

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What does "equivalent" mean in math?

butalik [34]

In math, equivalent means equal to.

6 0

3 years ago

I NEED HELP ASAP PLEASE!!!

Colt1911 [192]

Answer:

h= 2/3d

Step-by-step explanation:

slope is the change of y value on the change of x value

4/6 = 2/3

3 0

3 years ago

4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?

Alexeev081 [22]

Distance between T(80, 20) and U(20, 60) = sqrt((20 - 80)^2 + (60 - 20)^2) = sqrt((-60)^2 + (40)^2) = sqrt(3600 + 1600) = sqrt(5200) = 72.11 units

Distance between T(80, 20) and V(110, 85) = sqrt((110 - 80)^2 + (85 - 20)^2) = sqrt((30)^2 + (65)^2) = sqrt(900 + 4225) = sqrt(5125) = 71.59

Distance between U(20, 60) and V(110, 85) = sqrt((110 - 20)^2 + (85 - 60)^2) = sqrt((90)^2 + (25)^2) = sqrt(8100 + 625) = sqrt(8725) = 93.41

Therefore, shortest distance for the trip = 71.59 + 93.41 = 165 units.

4 0

4 years ago

PLEASE Help! <br><br> How much larger is 3 to the 5th power than 5 to the 3rd power?

grandymaker [24]

Well 3 to the 5th power is 243 and 5 to the 3rd power is 125 and 243-125 is 118

7 0

4 years ago

Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to o

Roman55 [17]

Answer:

$Range = 11-2=9$

$\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5$

$\sigma^2 =8.25 \approx 8.3$

$\sigma = \sqrt{8.25}= 2.87 \approx 2.9$

Step-by-step explanation:

Assuming this question: "Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. 2,3,4,5,6,7,8,9,10,11 "

Solution to the problem

The range is defined as $Range = Max -Min$ and if we replace we got:

$Range = 11-2=9$

Now we can calculate the population mean with this formula:

$\mu =\frac{\sum_{i=1}^n X_i}{N}$

And if we replace we got:

$\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5$

The population variance is given by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And after replace we got: $\sigma^2 =8.25 \approx 8.3$

And the population standard deviation would be just the square root of the variance and we got:

$\sigma = \sqrt{8.25}= 2.87 \approx 2.9$

4 0

4 years ago