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saveliy_v [14]
3 years ago
7

Posting a screenshot.

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
Since 6 is positive, it's (x+blank)^2

6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
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The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.9 days and a standard de
FrozenT [24]
The 70th percentile is the same as the cutoff recovery time t such that every point above this time falls in the longest 30%, i.e.

\mathbb P(X>t)=0.30

Transform to the standard normal distribution:

\mathbb P\left(\dfrac{X-5.9}{2.5}>\dfrac{t-5.9}{2.5}\right)=\mathbb P(Z>t^*)

where t^* is the z-score corresponding to the cutoff time t, which is approximately t^*\approx0.5244. Solve for t:

t^*\approx0.5244=\dfrac{t-5.9}{2.5}\implies t\approx7.21\text{ days}
6 0
4 years ago
Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?
nignag [31]
3(8 – 4x) < 6(x – 5)?- 12x + 24 < 6x - 30
- 12x - 6x < - 30 - 24
- 18x < - 54 .(- 1)
  18x > 54
      x > 54/18
      x > 3
6 0
3 years ago
Read 2 more answers
13 + 11s = -15 + 8s − 20
koban [17]

<em>Answer,</em>

<em><u>S = -16</u></em>

<em>Explanation,</em>

<em><u>Step 1: Simplify both sides of the equation.</u></em>

<em>13 + 11s = − 15 + 8s − 20</em>

<em>13 + 11s = − 15 + 8s + − 20</em>

<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>

<em>11s + 13 = 8s + − 35</em>

<em>11s + 13 = 8s − 35</em>

<em><u>Step 2: Subtract 8s from both sides.</u></em>

<em>11s + 13 − 8s = 8s − 35 − 8s</em>

<em>3s + 13 = − 35</em>

<em>Step 3: Subtract 13 from both sides.</em>

<em>3s + 13 − 13 = − 35 − 13</em>

<em>3s = − 48</em>

<em><u>Step 4: Divide both sides by 3.</u></em>

<em>3s/3 = −48/3</em>

<em>s = -16</em>


<u><em>Hope this helps :-)</em></u>


3 0
3 years ago
Write an equation of a line with the given slope and y-intercept. m = –5, b = –3. A. y = –5x – 3 . B. y = –5x + 3 . C. y = 5x –
True [87]
Y = mx + b
y = -5x -3

5 0
3 years ago
Read 2 more answers
How do I start this problem? I don't need help with the graphing part.
tamaranim1 [39]

Answer:

x = 6 , y = 0   (x , y) = (6 , 0)

x = 12, y = 3   (x , y) = (12 , 3)

x = 24, y = 9   (x , y) = (24 , 9)

Step-by-step explanation:

Simply plug in a x, and find a y that would make the equation true:

When x = 6:

6 - 2y = 6

6 (-6) - 2y = 6 (-6)

-2y = 0

(-2y)/-2 = (0)/-2

y = 0

When x = 6, y = 0    (x , y) = (6 , 0)

When x = 12:

12 - 2y = 6

12 (-12) -2y = 6 (-12)

-2y = -6

(-2y)/-2 = (-6)/-2

y = 3

When x = 12, y = 3   (x , y) = (12 , 3)

When x = 24:

24 - 2y = 6

24 (-24) - 2y = 6 (-24)

-2y = -18

(-2y)/-2 = (-18)/-2

y = 9

When x = 24, y = 9   (x , y) = (24 , 9)

~

3 0
3 years ago
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