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3 years ago

9

Which is the solution to the inequality?

1 answer:

makvit [3.9K]2 years ago

6 0

Answer:

b>3.133333333

Step-by-step explanation:

13/5<b-8/15

13/5+8/15<b

39+8/15<b

47/15<b

3.13333333<b

b>3.13333333

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Evaluate the given expression at x= -4<br> -3x + 2x^2 + 2

Mkey [24]

Answer:

$\huge{ \boxed{ \bold{ \text{46}}}}$

Step-by-step explanation:

If the value of variables of algebraic expression are given, the value of the term or expression can easily obtained by replacing the variables with numbers.

$\text{ \underline{ Given}} : \text{x = - 4}$

$\text{ \underline{ To \: find}} : \sf{value \: of \: - 3x + 2 {x}^{2} + 2}$

$\text{ Plug \: the \: value \: of \: x}$

$➝ \: \sf{ - 3 * (- 4 )+ 2 * {( - 4)}^{2} + 2}$

$\text{Remember!} : \text{Multiplying \: a \: negative \: integer \: by \: negative \: integer \: gives \: a \: positive \: integer.}$

➝ $\sf{12 + 2 * {( - 4)}^{2} + 2}$

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$\text{Multiply \: the \: numbers}$

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$\text{Add \: the \: numbers}$

$➝ \boxed { \text{46}}$

$\text{Hope \: I \: helped!}$

$\text{Best \: regards!}$

~ $\text{TheAnimeGirl}$

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3 years ago

Read 2 more answers

What is a constant?<br> -a mathematical operator<br> -a variable<br> -a number

lidiya [134]

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3 years ago

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Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

ozzi

Answer:

$10.9\ \text{m/s}^2$

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

$\mu$ = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

$F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2$

La aceleración del bloque es $10.9\ \text{m/s}^2$ .

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3 years ago