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gregori [183]
2 years ago
9

Which is the solution to the inequality?

Mathematics
1 answer:
makvit [3.9K]2 years ago
6 0

Answer:

b>3.133333333

Step-by-step explanation:

13/5<b-8/15

13/5+8/15<b

39+8/15<b

47/15<b

3.13333333<b

b>3.13333333

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Evaluate the given expression at x= -4<br> -3x + 2x^2 + 2
Mkey [24]

Answer:

\huge{ \boxed{ \bold{ \text{46}}}}

Step-by-step explanation:

If the value of variables of algebraic expression are given, the value of the term or expression can easily obtained by replacing the variables with numbers.

\text{ \underline{ Given}} :  \text{x =  - 4}

\text{ \underline{ To \: find}} :  \sf{value \: of \:  - 3x + 2 {x}^{2}  + 2}

\text{  Plug \: the \: value \: of \: x}

➝ \:  \sf{ - 3 * (- 4 )+ 2 *  {( - 4)}^{2}  + 2}

\text{Remember!} :  \text{Multiplying \: a \: negative \: integer \: by \: negative \: integer \: gives \: a \: positive \: integer.}

➝\sf{12 + 2 *  {( - 4)}^{2}  + 2}

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➝\text{12 + 2 * 16 + 2}

\text{Multiply \: the \: numbers}

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\text{Add \: the \: numbers}

➝  \boxed { \text{46}}

\text{Hope \: I \: helped!}

\text{Best \: regards!}

~\text{TheAnimeGirl}

7 0
3 years ago
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Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s
ozzi

Answer:

10.9\ \text{m/s}^2

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

\mu = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2

La aceleración del bloque es 10.9\ \text{m/s}^2.

8 0
3 years ago
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