When a number is 3 times a first number. A third number is 100 more than the first number and the sum of the three numbers is 450, the numbers are 70, 170 and 210.
<h3>How to calculate the numbers?</h3>
Let the first number = x
Second number = 3x
Third number = x + 100
Sum = 450
The numbers will be:
x + 3x + x + 100 = 450
5x + 100 = 450
5x = 450 - 100
5x = 350
Divide
x = 350 / 5
x = 70
First number = 70
Second number = 3x = 3 × 70 = 210
Third number = x + 100 = 70 + 100 = 170
Therefore, the numbers are 70, 170 and 210.
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One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 450 , find the numbers.
X+8>= 18
therefore, the circle has to be on ten, (solid) and an arrow pointing to the right,
10+8>=18 which is true.
-7+x>= -8
the circle is going to be on -1, (solid) and pointing to the right.
-7 +-1 (-8) >=-8 which is true, then -7 +0>= -8 which is true
n-2<=4 so, the answer is a dot (solid) on 6 pointing to the left
6-2 (4) <=4 then 5-2 (3) <= 4 which both are true
-18+n<-7
so this answer is going to be on 10, and it will be a hollow dot, pointing to the left
-18+10 (-8) <-7 which is true
n-4>=13
so, this has to be greater than or equal to 13.
n must be greater than or equal to 17 (add 4 to both sides) so the dot (solid) is going to be on 17 and pointing to the right.
NOTICE: I had a different explanation for number 9, which is how I figured each one out.
Hope this helped! Sorry it took so long!
Answer:
Find the place value you want (the "rounding digit") and look at the digit just to the right of it.
If that digit is less than 5, do not change the rounding digit but drop all digits to the right of it.
If that digit is greater than or equal to five, add one to the rounding digit and drop all digits to the right of it.
Step-by-step explanation:
