Question

The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s2. A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the height of the rocket after t seconds? s(t) = –4.9t2 + 39.2 s(t) = –4.9t2 + 39.2t s(t) = –4.9t2 + 39.2t + 39.2 s(t) = –4.9t2 + 39.2t – 39.2

Answer 1

Answer:

s(t) = -4.9t² + 39.2t

Step-by-step explanation:

Given the projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s²

Given

g = -4.9m/s²

v0 = 39.2m/s

s0 = 0m (the initial height)

On substituting into the formula;

s(t) = gt² + v0t + s0

s(t) = -4.9t² + 39.2t + 0

s(t) = -4.9t² + 39.2t

This gives the equation that models the height