Question

PLEASE HELP! A 0.423 kg object carries a +11.5 uc

Answer 1

Answer:

2.15 m/s²

Explanation:

We'll begin by calculating the force of attraction between two charges. This can be obtained as follow:

Charge of 1st object (q₁) = +11.5 μC = +11.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.55 μC = –7.55×10¯⁶ C

Electrical constant (K) = 9×10⁹ Nm²/C²

Distance apart (r) = 0.925 m

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 11.5×10¯⁶ × 7.55×10¯⁶/ 0.925²

F = 0.781425 / 0.855625

F = 0.91 N

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass of object (m) = 0.423 Kg

Force (F) = 0.91 N

Acceleration (a) =?

F = ma

0.91 = 0.423 × a

Divide both side by 0.423

a = 0.91 / 0.423

a = 2.15 m/s²

Thus, the magnitude of the object's acceleration is 2.15 m/s²