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lozanna [386]
3 years ago
7

Need these 2 answered. 25 points! Please show work, Thanks! :)

Mathematics
2 answers:
adoni [48]3 years ago
5 0

Answer:

  • 2(x+3)(x+5)
  • -4(x+2)(x-4)

Step-by-step explanation:

1.

2x^2+16x +30\\\\\mathrm{Factor\:out\:common\:term\:}2:\\\quad 2\left(x^2+8x+15\right)\\\\\mathrm{Factor}\:x^2+8x+15:\\\quad \left(x+3\right)\left(x+5\right)\\\\\\=2\left(x+3\right)\left(x+5\right)

2.

-4x^2+8x+32\\\\\mathrm{Factor\:out\:common\:term\:}-4:\\\quad -4\left(x^2-2x-8\right)\\\\\mathrm{Factor}\:x^2-2x-8:\\\quad \left(x+2\right)\left(x-4\right)\\\\=-4\left(x+2\right)\left(x-4\right)

sasho [114]3 years ago
3 0
Hello!

1. -4x2 + 8x + 32
-4(x2 - 2x - 8)
-4(x2 + 2x - 4x - 8)
-4(x(x + 2) - 4(x + 2))
-4(x + 2)(x - 4)
Answer A.

2. 2x2 + 16x + 30
2(x2 + 8x + 15)
2(x2 + 5x + 3x + 15)
2(x(x + 5) + 3(x + 5))
2(x + 5)(x + 3)
Answer C.

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SVETLANKA909090 [29]

Answer:

r  = 6

Step-by-step explanation:

To get the value of r we will use the pythagoras theorem a shown;

PR² = QR² + PQ²

(4+r)² = 8² + r²

Expand

16+8r+r² = 64 + r²

16 + 8r = 64

8r = 64 - 16

8r = 48

r = 48/8

r = 6

Hence the value of r is 6

7 0
2 years ago
The perimeter of a rectangular piece of plastic is 14 millimeters. The piece of plastic is 3 millimeters tall. How wide is it?
laiz [17]
It gives the perimeter of 14 mm and if it is 3 mm tall, times that by 2 to get 6 for the total of both side then subtract 6 from 14 and you get 8 and then divide that by 2

Answer is 4 mm wide for the two sides
7 0
3 years ago
Get the product using FOIL method: (x+2)(x+3)
emmasim [6.3K]

Answer:

x² + 5x + 6

Step-by-step explanation:

Foil means first, outside, inside, last

First: (x+2)(x+3)

x × x = x²

Inside: (x+2)(x+3)

x × 3 = 3x

Ouside: (x+2)(x+3)

2 × x = 2x

Last: (x+2)(x+3)

2 × 3 = 6

adding them together:

x² + 3x + 2x + 6 = x² + 5x + 6

8 0
2 years ago
A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre
Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

N=2.85 rev/s

angular velocity \omega =2\pi N=17.90 rad/s

mass of objects m=1.5 kg

distance of objects from stool r_1=0.789 m

Combined moment of inertia of stool and student =5.53 kg.m^2

Now student pull off his hands so as to increase its speed to 3.60 rev/s

\omega _2=2\pi N_2

\omega _2=2\pi 3.6=22.62 rad/s

Initial moment of inertia of two masses I_0=2mr_^2

I_0=2\times 1.5\times (0.789)^2=1.867

After Pulling off hands so that r' is the distance of masses from stool

I_0'=2\times 1.5\times (r')^2

Conserving angular momentum

I_1\omega =I_2\omega _2

(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62

I_0'=1.397\times 0.791

I_0'=5.851

5.53+2\times 1.5\times (r')^2=5.851

2\times 1.5\times (r')^2=0.321

r'^2=0.107009

r'=0.327 m

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3 years ago
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Personally I would say C because when you take good notes you can go over what you don’t remember. You can also use your notes as a study guide.
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