Answer:
−7k^4−11k^2+6
Step-by-step explanation:
−4k^4+14+3k^2−3k^4−14k^2−8
(−4k^4+−3k^4)+(3k^2+−14k^2)+(14+−8)
−7k^4−11k^2+6
...
Answer:
Option (b) is correct.

Step-by-step explanation:
Given: 
We have too choose the correct simplification for the given statement.
Consider 
Using property of exponents,
We have,

Again applying property of exponents 
We have,

Simplify, we have,

we get,

Thus, 
Option (b) is correct.
Answer:
y=4.5
Step-by-step explanation:
2y+3=11
2y=11-3
2y=9
y= 4.5
Answer: 1
Step-by-step explanation: the cosine function oscillates between the values -1 to 1
The amplitude of this particular function is understood to be 1