If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Density = m/v
3.86kg=3860g
d= 3860/200
= 19.3g/cm^3
therefore it is gold.
Answer:
G=3/W
Step-by-step explanation:
Solve for g by dividing both sides by 3. So you get g=W/3.
The length of the base is 27 and the length of the height is 17.
To find the answer, you need to add up each side twice and set it equal to 88.
x-6+x-6+x+4+x+4=88
That is equal to: 4x - 4 = 88
Add 4 to both sides: 4x = 92
Divide by 4: x = 23
Now plug 23 in for x:
Base: 23 + 4 = 27
Height: 23-6=17
Answer:
d) This is a completely randomized design with two explanatory variables (factors).
Step-by-step explanation:
Explanatory variables are independent variables.
In this case, I prepared two explanatory variables, which are : (i)30-second ad
(ii) 60-second ad,
Then, the explanatory variables were assigned to 4 treatment groups, and each variable is done once or thrice.
All subjects are assigned randomly to all treatment groups, with each treatment group seeing one. We can conclude that this is a completely randomized design with two explanatory variables.
