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Nimfa-mama [501]
2 years ago
10

Dexter paid $74.94 for 201/5 gallons of gas. What's the price of gas where Dexter filled up his vehicle?

Mathematics
1 answer:
densk [106]2 years ago
3 0

Answer:

$1.90 approx

Step-by-step explanation:

Given data

Amount paid=  $74.94

Amount of gallons=  201/5 gallons of gas

= 201/5

=40.2 gallons

let us find the unit cost per gallons

Unit cost per gallon is = 74.94/40.2

Unit cost per gallon=$1.86

The price of gas is $1.90 approx

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(please show work!!!)
dmitriy555 [2]
The variable “x” can be defined as the price of regular gas.
The equation is x = x - (.02)7
x = x - (.02)7
(.02)7 = .14
x = x - .14
 X - X = nothing so it just leaves you with -.14
The answer is that the gas price changed by a total of - 14 cents or -0.14
7 0
2 years ago
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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3 years ago
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Answer:

Step-by-step explanation:

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BabaBlast [244]

Answer:

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Step-by-step explanation:

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