Question

Find Y Special right triangles Please last question of the day!! Due very soon

Answer 1

Given:

A right triangle with angles 30, 60, 90 degrees.

Hypotenuse = $2\sqrt{2}$ mm.

Base = y

To find:

The value of y.

Solution:

In a right angle triangle,

$\cos \theta = \dfrac{Base}{Hypotenuse}$

$\cos (60^\circ)= \dfrac{y}{2\sqrt{2}}$

$\dfrac{1}{2}=\dfrac{y}{2\sqrt{2}}$

$\dfrac{2\sqrt{2}}{2}=y$

$\sqrt{2}=y$

Therefore, the value of y is $\sqrt{2}$ mm.