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3 years ago

Help help me please?

Physics

1 answer:

Sladkaya [172]3 years ago

6 0

Answer:

thats tough i would just guess

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Suppose that a spiral galaxy is located at the center of a spherically symmetric dark matter halo

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PART B) This time we have $v=\omega t$ , where $\omega$ is the angular velocity (constant at this case)

$\frac{4\pi G\rho r}{3} = \frac{v^2}{r}$

$\frac{4\pi G\rho r}{3} = \frac{(\omega r)^2}{r}$

$\rho = \frac{3\omega r}{4\pi Gr}$

$\rho = \frac{3\omega^2}{4\pi G} \propto constant$

PART C) If the total mass interior to any radius r is a constant,

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4 years ago

what is the magnitude of the compression forces (assumed to be horizontal) acting on both sides of the center board that is sand

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F = normal force by each board on each side

W = weight of the board in between acting in down direction = 95.5 N

f = frictional force in upward direction by each board

$\mu$ = coefficient of friction = 0.663

Using equilibrium of force in Upward direction

f + f = W

f = W/2

f = 95.5/2 = 47.75 N

frictional force is given as

f = $\mu$ F

47.75 = (0.663) F

F = 72.02 N

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3 years ago

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