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3 years ago

14

Which graph represents the relationship between the magnitude of the gravitational force exerted by earth on a spacecraft the di

stance between the center of the spacecraft the center of earth

1 answer:

Neko [114]3 years ago

8 0

Answer:

B as distance increase force decrease, but it is not a linear relationship.

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Convert 9/4 hours into minutes

Eduardwww [97]

Am guessing;

9/4 × 60/1 =135

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3 years ago

If an item as a density of.63 g/mL, when placed in water the item will

sergij07 [2.7K]

Float. This is because water has a density of 1 g/ml, so anything less than this will float.

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4 years ago

Which is a correct name for the compound Cuci?

guapka [62]

Copper(I) chloride, commonly called cuprous chloride, is the lower chloride of copper, with the formula CuCl.

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4 years ago

An audi travels at 88 km/hr over a distance of 22 km. calculate.25 the time taken for the audi to travel this distance.

sammy [17]

The Audi covers 88 in one hour.
22 is one quarter of 88, so it takes one quarter of one hour. That's 15 minutes.
Note:. The answer would be the same for any other brand of car, motorcycle, airplane etc.

4 0

4 years ago

When the mass is removed, the length of the cable is found to be l0 = 4.66 m. After the mass is added, the length is remeasured

zaharov [31]

Answer:

$\gamma=6.07*10^5\frac{N}{m^2}$

Explanation:

For a linear elastic material Young's modulus is a constant that is given by:

$\gamma=\frac{F/A}{\Delta L/L_0}$

Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, $\Delta L$ is the amount by which the length of the object changes and $L_0$ is the original length of the object. In this case the force is the weight of the mass:

$F=mg\\F=55kg(9.8\frac{m}{s^2})\\F=539N$

Replacing the given values in Young's modulus formula:

$\gamma=\frac{F/\pi r^2}{(L_1-L_0)/L_0}\\\gamma=\frac{539N/\pi(0.045m)^2}{(5.31m-4.66m)/4.66m}\\\gamma=6.07*10^5\frac{N}{m^2}$

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3 years ago